y^2+20x+10y-5=0

Lösung

y^{2} + 20 x + 10 y - 5 = 0

(h, k) = (\frac{3}{2}, - 5), p = - 5

Schritte zur Lösung

y^{2} + 20 x + 10 y - 5 = 0

Rewrite

y^{2} + 20 x + 10 y - 5 = 0

in the standard form

4 (- 5) (x - \frac{3}{2}) = (y - (- 5))^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{2}, - 5), p = - 5

x = y^{2} - 8 y + 18

(x - 2)^{2} = - 53 y

10 y = - 5 x^{2} + 8

(x - 3) 2 + \frac{y ^{2}}{4} = 1

x = 2 x - y^{2}