y^2+16x+4y+4=0

Lösung

y^{2} + 16 x + 4 y + 4 = 0

(h, k) = (0, - 2), p = - 4

Schritte zur Lösung

y^{2} + 16 x + 4 y + 4 = 0

Rewrite

y^{2} + 16 x + 4 y + 4 = 0

in the standard form

4 (- 4) (x - 0) = (y - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (0, - 2), p = - 4

x = - y^{2} + 14

(x + 2)^{2} = - 16 (y - 3)

y > x^{2} + 3 x - 4

y^{2} - 4 y - x + 3 = 0

(x + 3)^{2} = 24 (y + 3)