4x^2-12y-9=0

Lösung

4 x^{2} - 12 y - 9 = 0

(h, k) = (0, - \frac{3}{4}), p = \frac{3}{4}

Schritte zur Lösung

4 x^{2} - 12 y - 9 = 0

Rewrite

4 x^{2} - 12 y - 9 = 0

in the standard form:

4 \cdot \frac{3}{4} (y - (- \frac{3}{4})) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - \frac{3}{4}), p = \frac{3}{4}

y^{2} = \frac{- 2 + 2 x}{3}

x^{2} - 8 x + q (x) = 0

y^{2} + 4 y + 4 = x

x^{2} + x + 6 k (x) > 0

3 x^{2} - y = 5 - x + 2 y