-y^2+x-4=0

Lösung

- y^{2} + x - 4 = 0

(h, k) = (4, 0), p = \frac{1}{4}

Schritte zur Lösung

- y^{2} + x - 4 = 0

Rewrite

- y^{2} + x - 4 = 0

in the standard form:

4 \cdot \frac{1}{4} (x - 4) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (4, 0), p = \frac{1}{4}

y \geq x^{2} - 6

y \geq x^{2} - 5

2 y^{2} - x - 3 y - 4 = 0

3000 - p^{2} + 2 q = 0

x^{2} - 24 y = 0