y<=-x^2-6

Lösung

y \leq - x^{2} - 6

(h, k) = (0, - 6), p = - \frac{1}{4}

Schritte zur Lösung

y \leq - x^{2} - 6

Rewrite

y \leq - x^{2} - 6

in the standard form:

4 (- \frac{1}{4}) (y - (- 6)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 6), p = - \frac{1}{4}

y \leq - x^{2} - 7

f (x) \leq x^{2}

3 x^{2} - 6 y + 9 = 2 y - 6 x + 5

(y + 10)^{2} = x

(x + 1)^{2} = - 8 y + 16