x^2+y<= 9

Lösung

x^{2} + y \leq 9

(h, k) = (0, 9), p = - \frac{1}{4}

Schritte zur Lösung

x^{2} + y \leq 9

Rewrite

x^{2} + y \leq 9

in the standard form:

4 (- \frac{1}{4}) (y - 9) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 9), p = - \frac{1}{4}

4 y^{2} + 8 y + 16 - x = 0

2 y^{2} - 9 x = 0

(x - 3)^{2} = - 8 (y + 5)

4 x^{2} - 20 x + 24 y + 97 = 0

y = \frac{x}{y}