4x^2-20x+24y+97=0

Lösung

4 x^{2} - 20 x + 24 y + 97 = 0

(h, k) = (\frac{5}{2}, - 3), p = - \frac{3}{2}

Schritte zur Lösung

4 x^{2} - 20 x + 24 y + 97 = 0

Rewrite

4 x^{2} - 20 x + 24 y + 97 = 0

in the standard form

4 (- \frac{3}{2}) (y - (- 3)) = (x - \frac{5}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{5}{2}, - 3), p = - \frac{3}{2}

y = \frac{x}{y}

y = \frac{3 x}{4 y}

y 7 y + 5 + 9 x + 2 = 180

(x + 13)^{2} = 8 (y + 5)

y = 2 x^{2} - 16 x + 28