2(x-3)^2=(y-5)

Lösung

2 (x - 3)^{2} = (y - 5)

(h, k) = (3, 5), p = \frac{1}{8}

Schritte zur Lösung

2 (x - 3)^{2} = (y - 5)

Rewrite

2 (x - 3)^{2} = (y - 5)

in the standard form:

4 \cdot \frac{1}{8} (y - 5) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, 5), p = \frac{1}{8}

8 (x + 0) = (y + 0)^{2}

4 x^{2} - y = 5

4 x^{2} + 7 x + k (x) = 0

y^{2} - 3 x + 1 = 5 x

- x^{2} - 5 y + 6 \geq 0