y^2-3x+1=5x

Lösung

y^{2} - 3 x + 1 = 5 x

(h, k) = (\frac{1}{8}, 0), p = 2

Schritte zur Lösung

y^{2} - 3 x + 1 = 5 x

Rewrite

y^{2} - 3 x + 1 = 5 x

in the standard form:

4 \cdot 2 (x - \frac{1}{8}) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{8}, 0), p = 2

- x^{2} - 5 y + 6 \geq 0

4 x^{2} - y = 3

4 x^{2} - y = 1

y^{2} - 14 y - 4 x + 33 = 0

(x - 0)^{2} = 4 (- \frac{5}{12}) (y - 0)