zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的 Geometry >

solvefor f,f=6(x-2)f(x)^{-1}(x)f-1(x)

解答

求解

f, f = 6 (x - 2) f (x)^{- 1} (x) f - 1 (x)

解答

f = \frac{1 + 1 + 4 x ( 6 x - 12 )}{2 ( 6 x - 12 )}, f = \frac{1 - 1 + 4 x ( 6 x - 12 )}{2 ( 6 x - 12 )}; x \neq = 2

求解步骤

f = 6 (x - 2) f x^{- 1} (x) f - 1 \cdot (x)

展开

6 (x - 2) f x^{- 1} (x) f - 1 \cdot (x) : 6 x f^{2} - 12 f^{2} - x

f = 6 x f^{2} - 12 f^{2} - x

交换两边

6 x f^{2} - 12 f^{2} - x = f

将

f

para o lado esquerdo

6 x f^{2} - 12 f^{2} - x - f = 0

改写成标准形式

a x^{2} + b x + c = 0

(6 x - 12) f^{2} - f - x = 0

使用求根公式求解

f_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( 6 x - 12 ) ( - x )}{2 ( 6 x - 12 )}

化简

(- 1)^{2} - 4 (6 x - 12) (- x) : 1 + 4 x (6 x - 12)

f_{1, 2} = \frac{- ( - 1 ) \pm 1 + 4 x ( 6 x - 12 )}{2 ( 6 x - 12 )}; x \neq = 2

将解分隔开

f_{1} = \frac{- ( - 1 ) + 1 + 4 x ( 6 x - 12 )}{2 ( 6 x - 12 )}, f_{2} = \frac{- ( - 1 ) - 1 + 4 x ( 6 x - 12 )}{2 ( 6 x - 12 )}

f = \frac{- ( - 1 ) + 1 + 4 x ( 6 x - 12 )}{2 ( 6 x - 12 )} : \frac{1 + 1 + 4 x ( 6 x - 12 )}{2 ( 6 x - 12 )}

f = \frac{- ( - 1 ) - 1 + 4 x ( 6 x - 12 )}{2 ( 6 x - 12 )} : \frac{1 - 1 + 4 x ( 6 x - 12 )}{2 ( 6 x - 12 )}

二次方程组的解是:

f = \frac{1 + 1 + 4 x ( 6 x - 12 )}{2 ( 6 x - 12 )}, f = \frac{1 - 1 + 4 x ( 6 x - 12 )}{2 ( 6 x - 12 )}; x \neq = 2

作图

流行的例子

(x-3)/(2^2)-(y^2)/(2^2)=1

\frac{x - 3}{2 ^{2}} - \frac{y ^{2}}{2 ^{2}} = 1

(y - 3)^{2} = 7 (x - 8)

x=((y^{(2)}+5))/((2))

x = \frac{( y ^{(2)} + 5 )}{( 2 )}

x = - 3 (y - 2)^{2} + 1

y^{2} = - (x - 4)