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Popular Trigonometry >

3sec^2(2x)=4

  • Pre Algebra
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Solution

3sec2(2x)=4

Solution

x=12π​+πn,x=1211π​+πn,x=125π​+πn,x=127π​+πn
+1
Degrees
x=15∘+180∘n,x=165∘+180∘n,x=75∘+180∘n,x=105∘+180∘n
Solution steps
3sec2(2x)=4
Solve by substitution
3sec2(2x)=4
Let: sec(2x)=u3u2=4
3u2=4:u=323​​,u=−323​​
3u2=4
Divide both sides by 3
3u2=4
Divide both sides by 333u2​=34​
Simplifyu2=34​
u2=34​
For x2=f(a) the solutions are x=f(a)​,−f(a)​
u=34​​,u=−34​​
34​​=323​​
34​​
Apply radical rule: assuming a≥0,b≥0=3​4​​
4​=2
4​
Factor the number: 4=22=22​
Apply radical rule: 22​=2=2
=3​2​
Rationalize 3​2​:323​​
3​2​
Multiply by the conjugate 3​3​​=3​3​23​​
3​3​=3
3​3​
Apply radical rule: a​a​=a3​3​=3=3
=323​​
=323​​
−34​​=−323​​
−34​​
Simplify 34​​:3​2​
34​​
Apply radical rule: assuming a≥0,b≥0=3​4​​
4​=2
4​
Factor the number: 4=22=22​
Apply radical rule: 22​=2=2
=3​2​
=−3​2​
Rationalize −3​2​:−323​​
−3​2​
Multiply by the conjugate 3​3​​=−3​3​23​​
3​3​=3
3​3​
Apply radical rule: a​a​=a3​3​=3=3
=−323​​
=−323​​
u=323​​,u=−323​​
Substitute back u=sec(2x)sec(2x)=323​​,sec(2x)=−323​​
sec(2x)=323​​,sec(2x)=−323​​
sec(2x)=323​​:x=12π​+πn,x=1211π​+πn
sec(2x)=323​​
General solutions for sec(2x)=323​​
sec(x) periodicity table with 2πn cycle:
x06π​4π​3π​2π​32π​43π​65π​​sec(x)1323​​2​2Undefined−2−2​−323​​​xπ67π​45π​34π​23π​35π​47π​611π​​sec(x)−1−323​​−2​−2Undefined22​323​​​​
2x=6π​+2πn,2x=611π​+2πn
2x=6π​+2πn,2x=611π​+2πn
Solve 2x=6π​+2πn:x=12π​+πn
2x=6π​+2πn
Divide both sides by 2
2x=6π​+2πn
Divide both sides by 222x​=26π​​+22πn​
Simplify
22x​=26π​​+22πn​
Simplify 22x​:x
22x​
Divide the numbers: 22​=1=x
Simplify 26π​​+22πn​:12π​+πn
26π​​+22πn​
26π​​=12π​
26π​​
Apply the fraction rule: acb​​=c⋅ab​=6⋅2π​
Multiply the numbers: 6⋅2=12=12π​
22πn​=πn
22πn​
Divide the numbers: 22​=1=πn
=12π​+πn
x=12π​+πn
x=12π​+πn
x=12π​+πn
Solve 2x=611π​+2πn:x=1211π​+πn
2x=611π​+2πn
Divide both sides by 2
2x=611π​+2πn
Divide both sides by 222x​=2611π​​+22πn​
Simplify
22x​=2611π​​+22πn​
Simplify 22x​:x
22x​
Divide the numbers: 22​=1=x
Simplify 2611π​​+22πn​:1211π​+πn
2611π​​+22πn​
2611π​​=1211π​
2611π​​
Apply the fraction rule: acb​​=c⋅ab​=6⋅211π​
Multiply the numbers: 6⋅2=12=1211π​
22πn​=πn
22πn​
Divide the numbers: 22​=1=πn
=1211π​+πn
x=1211π​+πn
x=1211π​+πn
x=1211π​+πn
x=12π​+πn,x=1211π​+πn
sec(2x)=−323​​:x=125π​+πn,x=127π​+πn
sec(2x)=−323​​
General solutions for sec(2x)=−323​​
sec(x) periodicity table with 2πn cycle:
x06π​4π​3π​2π​32π​43π​65π​​sec(x)1323​​2​2Undefined−2−2​−323​​​xπ67π​45π​34π​23π​35π​47π​611π​​sec(x)−1−323​​−2​−2Undefined22​323​​​​
2x=65π​+2πn,2x=67π​+2πn
2x=65π​+2πn,2x=67π​+2πn
Solve 2x=65π​+2πn:x=125π​+πn
2x=65π​+2πn
Divide both sides by 2
2x=65π​+2πn
Divide both sides by 222x​=265π​​+22πn​
Simplify
22x​=265π​​+22πn​
Simplify 22x​:x
22x​
Divide the numbers: 22​=1=x
Simplify 265π​​+22πn​:125π​+πn
265π​​+22πn​
265π​​=125π​
265π​​
Apply the fraction rule: acb​​=c⋅ab​=6⋅25π​
Multiply the numbers: 6⋅2=12=125π​
22πn​=πn
22πn​
Divide the numbers: 22​=1=πn
=125π​+πn
x=125π​+πn
x=125π​+πn
x=125π​+πn
Solve 2x=67π​+2πn:x=127π​+πn
2x=67π​+2πn
Divide both sides by 2
2x=67π​+2πn
Divide both sides by 222x​=267π​​+22πn​
Simplify
22x​=267π​​+22πn​
Simplify 22x​:x
22x​
Divide the numbers: 22​=1=x
Simplify 267π​​+22πn​:127π​+πn
267π​​+22πn​
267π​​=127π​
267π​​
Apply the fraction rule: acb​​=c⋅ab​=6⋅27π​
Multiply the numbers: 6⋅2=12=127π​
22πn​=πn
22πn​
Divide the numbers: 22​=1=πn
=127π​+πn
x=127π​+πn
x=127π​+πn
x=127π​+πn
x=125π​+πn,x=127π​+πn
Combine all the solutionsx=12π​+πn,x=1211π​+πn,x=125π​+πn,x=127π​+πn

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