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Popular Trigonometry >

solvefor t,g=sin(2pift)

  • Pre Algebra
  • Algebra
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Solution

solve for t,g=sin(2πft)

Solution

t=2πfarcsin(g)​+fn​,t=2f1​+2πfarcsin(−g)​+fn​
Solution steps
g=sin(2πft)
Switch sidessin(2πft)=g
Apply trig inverse properties
sin(2πft)=g
General solutions for sin(2πft)=gsin(x)=a⇒x=arcsin(a)+2πn,x=π+arcsin(a)+2πn2πft=arcsin(g)+2πn,2πft=π+arcsin(−g)+2πn
2πft=arcsin(g)+2πn,2πft=π+arcsin(−g)+2πn
Solve 2πft=arcsin(g)+2πn:t=2πfarcsin(g)​+fn​;f=0
2πft=arcsin(g)+2πn
Divide both sides by 2πf;f=0
2πft=arcsin(g)+2πn
Divide both sides by 2πf;f=02πf2πft​=2πfarcsin(g)​+2πf2πn​;f=0
Simplify
2πf2πft​=2πfarcsin(g)​+2πf2πn​
Simplify 2πf2πft​:t
2πf2πft​
Divide the numbers: 22​=1=πfπtf​
Cancel the common factor: π=ftf​
Cancel the common factor: f=t
Simplify 2πfarcsin(g)​+2πf2πn​:2πfarcsin(g)​+fn​
2πfarcsin(g)​+2πf2πn​
Cancel 2πf2πn​:fn​
2πf2πn​
Cancel 2πf2πn​:fn​
2πf2πn​
Divide the numbers: 22​=1=πfπn​
Cancel the common factor: π=fn​
=fn​
=2πfarcsin(g)​+fn​
t=2πfarcsin(g)​+fn​;f=0
t=2πfarcsin(g)​+fn​;f=0
t=2πfarcsin(g)​+fn​;f=0
Solve 2πft=π+arcsin(−g)+2πn:t=2f1​+2πfarcsin(−g)​+fn​;f=0
2πft=π+arcsin(−g)+2πn
Divide both sides by 2πf;f=0
2πft=π+arcsin(−g)+2πn
Divide both sides by 2πf;f=02πf2πft​=2πfπ​+2πfarcsin(−g)​+2πf2πn​;f=0
Simplify
2πf2πft​=2πfπ​+2πfarcsin(−g)​+2πf2πn​
Simplify 2πf2πft​:t
2πf2πft​
Divide the numbers: 22​=1=πfπtf​
Cancel the common factor: π=ftf​
Cancel the common factor: f=t
Simplify 2πfπ​+2πfarcsin(−g)​+2πf2πn​:2f1​+2πfarcsin(−g)​+fn​
2πfπ​+2πfarcsin(−g)​+2πf2πn​
Cancel 2πfπ​:2f1​
2πfπ​
Cancel the common factor: π=2f1​
=2f1​+2πfarcsin(−g)​+2πf2πn​
Cancel 2πf2πn​:fn​
2πf2πn​
Cancel 2πf2πn​:fn​
2πf2πn​
Divide the numbers: 22​=1=πfπn​
Cancel the common factor: π=fn​
=fn​
=2f1​+2πfarcsin(−g)​+fn​
t=2f1​+2πfarcsin(−g)​+fn​;f=0
t=2f1​+2πfarcsin(−g)​+fn​;f=0
t=2f1​+2πfarcsin(−g)​+fn​;f=0
t=2πfarcsin(g)​+fn​,t=2f1​+2πfarcsin(−g)​+fn​

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