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受欢迎的 三角函数 >

sqrt(1-cos^2(x))=0.75sqrt(1-cos^2(y))

  • 初等代数
  • 代数
  • 微积分入门
  • 微积分
  • 函数
  • 线性代数
  • 三角
  • 统计
  • 化学

解答

1−cos2(x)​=0.751−cos2(y)​

解答

x=arccos(0.5625cos2(y)+0.4375​)+2πn,x=−arccos(0.5625cos2(y)+0.4375​)+2πn,x=arccos(−0.5625cos2(y)+0.4375​)+2πn,x=−arccos(−0.5625cos2(y)+0.4375​)+2πn
求解步骤
1−cos2(x)​=0.751−cos2(y)​
用替代法求解
1−cos2(x)​=0.751−cos2(y)​
令:cos(x)=u1−u2​=0.751−cos2(y)​
1−u2​=0.751−cos2(y)​:u=0.5625cos2(y)+0.4375​,u=−0.5625cos2(y)+0.4375​
1−u2​=0.751−cos2(y)​
两边进行平方:1−u2=0.5625−0.5625cos2(y)
1−u2​=0.751−cos2(y)​
(1−u2​)2=(0.751−cos2(y)​)2
展开 (1−u2​)2:1−u2
(1−u2​)2
使用根式运算法则: a​=a21​=((1−u2)21​)2
使用指数法则: (ab)c=abc=(1−u2)21​⋅2
21​⋅2=1
21​⋅2
分式相乘: a⋅cb​=ca⋅b​=21⋅2​
约分:2=1
=1−u2
展开 (0.751−cos2(y)​)2:0.5625−0.5625cos2(y)
(0.751−cos2(y)​)2
使用指数法则: (a⋅b)n=anbn=0.752(−cos2(y)+1​)2
(1−cos2(y)​)2:1−cos2(y)
使用根式运算法则: a​=a21​=((1−cos2(y))21​)2
使用指数法则: (ab)c=abc=(1−cos2(y))21​⋅2
21​⋅2=1
21​⋅2
分式相乘: a⋅cb​=ca⋅b​=21⋅2​
约分:2=1
=1−cos2(y)
=0.752(1−cos2(y))
0.752=0.5625=0.5625(−cos2(y)+1)
使用分配律: a(b−c)=ab−aca=0.5625,b=1,c=cos2(y)=0.5625⋅1−0.5625cos2(y)
=1⋅0.5625−0.5625cos2(y)
数字相乘:1⋅0.5625=0.5625=0.5625−0.5625cos2(y)
1−u2=0.5625−0.5625cos2(y)
1−u2=0.5625−0.5625cos2(y)
解 1−u2=0.5625−0.5625cos2(y):u=0.5625cos2(y)+0.4375​,u=−0.5625cos2(y)+0.4375​
1−u2=0.5625−0.5625cos2(y)
将 1到右边
1−u2=0.5625−0.5625cos2(y)
两边减去 11−u2−1=0.5625−0.5625cos2(y)−1
化简−u2=−0.5625cos2(y)−0.4375
−u2=−0.5625cos2(y)−0.4375
两边除以 −1
−u2=−0.5625cos2(y)−0.4375
两边除以 −1−1−u2​=−−10.5625cos2(y)​−−10.4375​
化简
−1−u2​=−−10.5625cos2(y)​−−10.4375​
化简 −1−u2​:u2
−1−u2​
使用分式法则: −b−a​=ba​=1u2​
使用法则 1a​=a=u2
化简 −−10.5625cos2(y)​−−10.4375​:0.5625cos2(y)+0.4375
−−10.5625cos2(y)​−−10.4375​
使用法则 ca​±cb​=ca±b​=−1−0.5625cos2(y)−0.4375​
使用分式法则: −ba​=−ba​=−1−0.5625cos2(y)−0.4375​
使用法则 1a​=a=−(−0.5625cos2(y)−0.4375)
打开括号=−(−0.5625cos2(y))−(−0.4375)
使用加减运算法则−(−a)=a=0.5625cos2(y)+0.4375
u2=0.5625cos2(y)+0.4375
u2=0.5625cos2(y)+0.4375
u2=0.5625cos2(y)+0.4375
对于 x2=f(a) 解为 x=f(a)​,−f(a)​
u=0.5625cos2(y)+0.4375​,u=−0.5625cos2(y)+0.4375​
u=0.5625cos2(y)+0.4375​,u=−0.5625cos2(y)+0.4375​
验证解:u=0.5625cos2(y)+0.4375​真,u=−0.5625cos2(y)+0.4375​真
将它们代入 1−u2​=0.751−cos2(y)​检验解是否符合
去除与方程不符的解。
代入 u=0.5625cos2(y)+0.4375​:真
1−(0.5625cos2(y)+0.4375​)2​=0.751−cos2(y)​
化简 1−(0.5625cos2(y)+0.4375​)2​:−0.5625cos2(y)+0.5625​
1−(0.5625cos2(y)+0.4375​)2​
(0.5625cos2(y)+0.4375​)2=0.5625cos2(y)+0.4375
(0.5625cos2(y)+0.4375​)2
使用根式运算法则: a​=a21​=((0.5625cos2(y)+0.4375)21​)2
使用指数法则: (ab)c=abc=(0.5625cos2(y)+0.4375)21​⋅2
21​⋅2=1
21​⋅2
分式相乘: a⋅cb​=ca⋅b​=21⋅2​
约分:2=1
=0.5625cos2(y)+0.4375
=1−(0.5625cos2(y)+0.4375)​
乘开 1−(0.5625cos2(y)+0.4375):−0.5625cos2(y)+0.5625
1−(0.5625cos2(y)+0.4375)
−(0.5625cos2(y)+0.4375):−0.5625cos2(y)−0.4375
−(0.5625cos2(y)+0.4375)
打开括号=−(0.5625cos2(y))−(0.4375)
使用加减运算法则+(−a)=−a=−0.5625cos2(y)−0.4375
=1−0.5625cos2(y)−0.4375
数字相减:1−0.4375=0.5625=−0.5625cos2(y)+0.5625
=−0.5625cos2(y)+0.5625​
−0.5625cos2(y)+0.5625​=0.751−cos2(y)​
真
代入 u=−0.5625cos2(y)+0.4375​:真
1−(−0.5625cos2(y)+0.4375​)2​=0.751−cos2(y)​
化简 1−(−0.5625cos2(y)+0.4375​)2​:−0.5625cos2(y)+0.5625​
1−(−0.5625cos2(y)+0.4375​)2​
(−0.5625cos2(y)+0.4375​)2=0.5625cos2(y)+0.4375
(−0.5625cos2(y)+0.4375​)2
使用指数法则: (−a)n=an,若 n 是偶数(−0.5625cos2(y)+0.4375​)2=(0.5625cos2(y)+0.4375​)2=(0.5625cos2(y)+0.4375​)2
使用根式运算法则: a​=a21​=((0.5625cos2(y)+0.4375)21​)2
使用指数法则: (ab)c=abc=(0.5625cos2(y)+0.4375)21​⋅2
21​⋅2=1
21​⋅2
分式相乘: a⋅cb​=ca⋅b​=21⋅2​
约分:2=1
=0.5625cos2(y)+0.4375
=1−(0.5625cos2(y)+0.4375)​
乘开 1−(0.5625cos2(y)+0.4375):−0.5625cos2(y)+0.5625
1−(0.5625cos2(y)+0.4375)
−(0.5625cos2(y)+0.4375):−0.5625cos2(y)−0.4375
−(0.5625cos2(y)+0.4375)
打开括号=−(0.5625cos2(y))−(0.4375)
使用加减运算法则+(−a)=−a=−0.5625cos2(y)−0.4375
=1−0.5625cos2(y)−0.4375
数字相减:1−0.4375=0.5625=−0.5625cos2(y)+0.5625
=−0.5625cos2(y)+0.5625​
−0.5625cos2(y)+0.5625​=0.751−cos2(y)​
真
解为u=0.5625cos2(y)+0.4375​,u=−0.5625cos2(y)+0.4375​
u=cos(x)代回cos(x)=0.5625cos2(y)+0.4375​,cos(x)=−0.5625cos2(y)+0.4375​
cos(x)=0.5625cos2(y)+0.4375​,cos(x)=−0.5625cos2(y)+0.4375​
cos(x)=0.5625cos2(y)+0.4375​:x=arccos(0.5625cos2(y)+0.4375​)+2πn,x=−arccos(0.5625cos2(y)+0.4375​)+2πn
cos(x)=0.5625cos2(y)+0.4375​
使用反三角函数性质
cos(x)=0.5625cos2(y)+0.4375​
cos(x)=0.5625cos2(y)+0.4375​的通解cos(x)=a⇒x=arccos(a)+2πn,x=−arccos(a)+2πnx=arccos(0.5625cos2(y)+0.4375​)+2πn,x=−arccos(0.5625cos2(y)+0.4375​)+2πn
x=arccos(0.5625cos2(y)+0.4375​)+2πn,x=−arccos(0.5625cos2(y)+0.4375​)+2πn
cos(x)=−0.5625cos2(y)+0.4375​:x=arccos(−0.5625cos2(y)+0.4375​)+2πn,x=−arccos(−0.5625cos2(y)+0.4375​)+2πn
cos(x)=−0.5625cos2(y)+0.4375​
使用反三角函数性质
cos(x)=−0.5625cos2(y)+0.4375​
cos(x)=−0.5625cos2(y)+0.4375​的通解cos(x)=a⇒x=arccos(a)+2πn,x=−arccos(a)+2πnx=arccos(−0.5625cos2(y)+0.4375​)+2πn,x=−arccos(−0.5625cos2(y)+0.4375​)+2πn
x=arccos(−0.5625cos2(y)+0.4375​)+2πn,x=−arccos(−0.5625cos2(y)+0.4375​)+2πn
合并所有解x=arccos(0.5625cos2(y)+0.4375​)+2πn,x=−arccos(0.5625cos2(y)+0.4375​)+2πn,x=arccos(−0.5625cos2(y)+0.4375​)+2πn,x=−arccos(−0.5625cos2(y)+0.4375​)+2πn

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流行的例子

sec^2(x)-6tan(x)+4=0sec2(x)−6tan(x)+4=01-cos(x)=2-2sin^2(x)1−cos(x)=2−2sin2(x)-5tan(x)-12=tan(x)-8−5tan(x)−12=tan(x)−85=sec^2(x)+35=sec2(x)+3sin(θ)= 24/25sin(θ)=2524​
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