What is the general solution for tan^2(x)=tan^2(x)sec(x) ?

The general solution for tan^2(x)=tan^2(x)sec(x) is x=pin

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Popular Trigonometry >

tan^2(x)=tan^2(x)sec(x)

Solution

tan^{2} (x) = tan^{2} (x) sec (x)

Solution

x = πn

Degrees

x = 0^{\circ} + 18 0^{\circ} n

Solution steps

tan^{2} (x) = tan^{2} (x) sec (x)

Subtract

tan^{2} (x) sec (x)

from both sides

tan^{2} (x) - tan^{2} (x) sec (x) = 0

Factor

tan^{2} (x) - tan^{2} (x) sec (x) : - tan^{2} (x) (sec (x) - 1)

tan^{2} (x) - tan^{2} (x) sec (x)

Factor out common term

- tan^{2} (x)

= - tan^{2} (x) (- 1 + sec (x))

- tan^{2} (x) (sec (x) - 1) = 0

Solving each part separately

tan^{2} (x) = 0 or sec (x) - 1 = 0

tan^{2} (x) = 0 : x = πn

tan^{2} (x) = 0

Apply rule

x^{n} = 0 \Rightarrow x = 0

tan (x) = 0

General solutions for

tan (x) = 0

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = 0 + πn

x = 0 + πn

Solve

x = 0 + πn : x = πn

x = 0 + πn

0 + πn = πn

x = πn

x = πn

sec (x) - 1 = 0 : x = 2 πn

sec (x) - 1 = 0

Move

1

to the right side

sec (x) - 1 = 0

Add

1

to both sides

sec (x) - 1 + 1 = 0 + 1

Simplify

sec (x) = 1

sec (x) = 1

General solutions for

sec (x) = 1

sec (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

x = 0 + 2 πn

x = 0 + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn

Combine all the solutions

x = πn, x = 2 πn

Merge Overlapping Intervals

x = πn

Graph

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Frequently Asked Questions (FAQ)

What is the general solution for tan^2(x)=tan^2(x)sec(x) ?
The general solution for tan^2(x)=tan^2(x)sec(x) is x=pin