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受欢迎的三角函数 >

cos(θ)=sin(θ/3-10)

解答

cos (θ) = sin (\frac{θ}{3} - 1 0^{\circ})

解答

θ = \frac{324 0 ^{\circ} n + 90 0 ^{\circ}}{12}, θ = - \frac{90 0 ^{\circ} + 324 0 ^{\circ} n}{6}

+1

弧度

θ = \frac{5 π}{12} + \frac{18 π}{12} n, θ = - \frac{5 π}{6} - \frac{18 π}{6} n

求解步骤

cos (θ) = sin (\frac{θ}{3} - 1 0^{\circ})

使用三角恒等式改写

cos (θ) = sin (\frac{θ}{3} - 1 0^{\circ})

利用以下特性:

cos (x) = sin (9 0^{\circ} - x)

cos (θ) = sin (9 0^{\circ} - θ)

cos (θ) = sin (9 0^{\circ} - θ)

使用反三角函数性质

cos (θ) = sin (9 0^{\circ} - θ)

sin (x) = sin (y) \Rightarrow x = y + 2 π n, x = π - y + 2 π n

\frac{θ}{3} - 1 0^{\circ} = 9 0^{\circ} - θ + 36 0^{\circ} n, \frac{θ}{3} - 1 0^{\circ} = 18 0^{\circ} - (9 0^{\circ} - θ) + 36 0^{\circ} n

\frac{θ}{3} - 1 0^{\circ} = 9 0^{\circ} - θ + 36 0^{\circ} n, \frac{θ}{3} - 1 0^{\circ} = 18 0^{\circ} - (9 0^{\circ} - θ) + 36 0^{\circ} n

\frac{θ}{3} - 1 0^{\circ} = 9 0^{\circ} - θ + 36 0^{\circ} n : θ = \frac{324 0 ^{\circ} n + 90 0 ^{\circ}}{12}

\frac{θ}{3} - 1 0^{\circ} = 9 0^{\circ} - θ + 36 0^{\circ} n

将

1 0^{\circ}

到右边

\frac{θ}{3} - 1 0^{\circ} = 9 0^{\circ} - θ + 36 0^{\circ} n

两边加上

1 0^{\circ}

\frac{θ}{3} - 1 0^{\circ} + 1 0^{\circ} = 9 0^{\circ} - θ + 36 0^{\circ} n + 1 0^{\circ}

化简

\frac{θ}{3} - 1 0^{\circ} + 1 0^{\circ} = 9 0^{\circ} - θ + 36 0^{\circ} n + 1 0^{\circ}

化简

\frac{θ}{3} - 1 0^{\circ} + 1 0^{\circ} : \frac{θ}{3}

\frac{θ}{3} - 1 0^{\circ} + 1 0^{\circ}

同类项相加:

- 1 0^{\circ} + 1 0^{\circ} = 0

= \frac{θ}{3}

化简

9 0^{\circ} - θ + 36 0^{\circ} n + 1 0^{\circ} : - θ + 36 0^{\circ} n + 10 0^{\circ}

9 0^{\circ} - θ + 36 0^{\circ} n + 1 0^{\circ}

对同类项分组

= - θ + 36 0^{\circ} n + 9 0^{\circ} + 1 0^{\circ}

2, 18

的最小公倍数:

18

2, 18

最小公倍数 (LCM)

2

质因数分解:

2

2

2

是质数，因此无法因数分解

= 2

18

质因数分解:

2 \cdot 3 \cdot 3

18

18

除以

218 = 9 \cdot 2

= 2 \cdot 9

9

除以

39 = 3 \cdot 3

= 2 \cdot 3 \cdot 3

2, 3

都是质数，因此无法进一步因数分解

= 2 \cdot 3 \cdot 3

将每个因子乘以它在

2

或

18

中出现的最多次数

= 2 \cdot 3 \cdot 3

数字相乘:

2 \cdot 3 \cdot 3 = 18

= 18

根据最小公倍数调整分式

将每个分子乘以其分母转变为最小公倍数所要乘以的同一数值

18

对于

9 0^{\circ} :

将分母和分子乘以

9

9 0^{\circ} = \frac{18 0 ^{\circ} 9}{2 \cdot 9} = 9 0^{\circ}

= 9 0^{\circ} + 1 0^{\circ}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{18 0 ^{\circ} 9 + 18 0 ^{\circ}}{18}

同类项相加:

162 0^{\circ} + 18 0^{\circ} = 180 0^{\circ}

= 10 0^{\circ}

约分:

2

= - θ + 36 0^{\circ} n + 10 0^{\circ}

\frac{θ}{3} = - θ + 36 0^{\circ} n + 10 0^{\circ}

\frac{θ}{3} = - θ + 36 0^{\circ} n + 10 0^{\circ}

\frac{θ}{3} = - θ + 36 0^{\circ} n + 10 0^{\circ}

在两边乘以

3

\frac{θ}{3} = - θ + 36 0^{\circ} n + 10 0^{\circ}

在两边乘以

3

\frac{θ}{3} \cdot 3 = - θ \cdot 3 + 36 0^{\circ} n \cdot 3 + 10 0^{\circ} \cdot 3

化简

\frac{θ}{3} \cdot 3 = - θ \cdot 3 + 36 0^{\circ} n \cdot 3 + 10 0^{\circ} \cdot 3

化简

\frac{θ}{3} \cdot 3 : θ

\frac{θ}{3} \cdot 3

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{θ \cdot 3}{3}

约分:

3

= θ

化简

θ \cdot 3 : 3 θ

θ \cdot 3

使用交换律:

θ \cdot 3 = 3 θ

3 θ

化简

36 0^{\circ} n \cdot 3 : 108 0^{\circ} n

36 0^{\circ} n \cdot 3

数字相乘:

2 \cdot 3 = 6

= 108 0^{\circ} n

化简

10 0^{\circ} \cdot 3 : 30 0^{\circ}

10 0^{\circ} \cdot 3

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= 30 0^{\circ}

数字相乘:

5 \cdot 3 = 15

= 30 0^{\circ}

约分:

3

= 30 0^{\circ}

θ = - 3 θ + 108 0^{\circ} n + 30 0^{\circ}

θ = - 3 θ + 108 0^{\circ} n + 30 0^{\circ}

θ = - 3 θ + 108 0^{\circ} n + 30 0^{\circ}

将

3 θ

para o lado esquerdo

θ = - 3 θ + 108 0^{\circ} n + 30 0^{\circ}

两边加上

3 θ

θ + 3 θ = - 3 θ + 108 0^{\circ} n + 30 0^{\circ} + 3 θ

化简

4 θ = 108 0^{\circ} n + 30 0^{\circ}

4 θ = 108 0^{\circ} n + 30 0^{\circ}

两边除以

4

4 θ = 108 0^{\circ} n + 30 0^{\circ}

两边除以

4

\frac{4 θ}{4} = \frac{108 0 ^{\circ} n}{4} + \frac{30 0 ^{\circ}}{4}

化简

\frac{4 θ}{4} = \frac{108 0 ^{\circ} n}{4} + \frac{30 0 ^{\circ}}{4}

化简

\frac{4 θ}{4} : θ

\frac{4 θ}{4}

数字相除:

\frac{4}{4} = 1

= θ

化简

\frac{108 0 ^{\circ} n}{4} + \frac{30 0 ^{\circ}}{4} : \frac{324 0 ^{\circ} n + 90 0 ^{\circ}}{12}

\frac{108 0 ^{\circ} n}{4} + \frac{30 0 ^{\circ}}{4}

使用法则

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{108 0 ^{\circ} n + 30 0 ^{\circ}}{4}

化简

108 0^{\circ} n + 30 0^{\circ} : \frac{324 0 ^{\circ} n + 90 0 ^{\circ}}{3}

108 0^{\circ} n + 30 0^{\circ}

将项转换为分式:

108 0^{\circ} n = \frac{108 0 ^{\circ} n 3}{3}

= \frac{108 0 ^{\circ} n \cdot 3}{3} + 30 0^{\circ}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{108 0 ^{\circ} n \cdot 3 + 90 0 ^{\circ}}{3}

数字相乘:

6 \cdot 3 = 18

= \frac{324 0 ^{\circ} n + 90 0 ^{\circ}}{3}

= \frac{\frac{324 0 ^{\circ} n + 90 0 ^{\circ}}{3}}{4}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{324 0 ^{\circ} n + 90 0 ^{\circ}}{3 \cdot 4}

数字相乘:

3 \cdot 4 = 12

= \frac{324 0 ^{\circ} n + 90 0 ^{\circ}}{12}

θ = \frac{324 0 ^{\circ} n + 90 0 ^{\circ}}{12}

θ = \frac{324 0 ^{\circ} n + 90 0 ^{\circ}}{12}

θ = \frac{324 0 ^{\circ} n + 90 0 ^{\circ}}{12}

\frac{θ}{3} - 1 0^{\circ} = 18 0^{\circ} - (9 0^{\circ} - θ) + 36 0^{\circ} n : θ = - \frac{90 0 ^{\circ} + 324 0 ^{\circ} n}{6}

\frac{θ}{3} - 1 0^{\circ} = 18 0^{\circ} - (9 0^{\circ} - θ) + 36 0^{\circ} n

将

1 0^{\circ}

到右边

\frac{θ}{3} - 1 0^{\circ} = 18 0^{\circ} - (9 0^{\circ} - θ) + 36 0^{\circ} n

两边加上

1 0^{\circ}

\frac{θ}{3} - 1 0^{\circ} + 1 0^{\circ} = 18 0^{\circ} - (9 0^{\circ} - θ) + 36 0^{\circ} n + 1 0^{\circ}

化简

\frac{θ}{3} - 1 0^{\circ} + 1 0^{\circ} = 18 0^{\circ} - (9 0^{\circ} - θ) + 36 0^{\circ} n + 1 0^{\circ}

化简

\frac{θ}{3} - 1 0^{\circ} + 1 0^{\circ} : \frac{θ}{3}

\frac{θ}{3} - 1 0^{\circ} + 1 0^{\circ}

同类项相加:

- 1 0^{\circ} + 1 0^{\circ} = 0

= \frac{θ}{3}

化简

18 0^{\circ} - (9 0^{\circ} - θ) + 36 0^{\circ} n + 1 0^{\circ} : θ + 18 0^{\circ} + 36 0^{\circ} n - 8 0^{\circ}

18 0^{\circ} - (9 0^{\circ} - θ) + 36 0^{\circ} n + 1 0^{\circ}

- (9 0^{\circ} - θ) : - 9 0^{\circ} + θ

- (9 0^{\circ} - θ)

打开括号

= - (9 0^{\circ}) - (- θ)

使用加减运算法则

- (- a) = a, - (a) = - a

= - 9 0^{\circ} + θ

= 18 0^{\circ} - 9 0^{\circ} + θ + 36 0^{\circ} n + 1 0^{\circ}

化简

18 0^{\circ} - 9 0^{\circ} + θ + 36 0^{\circ} n + 1 0^{\circ} : θ + 18 0^{\circ} + 36 0^{\circ} n - 8 0^{\circ}

18 0^{\circ} - 9 0^{\circ} + θ + 36 0^{\circ} n + 1 0^{\circ}

对同类项分组

= θ + 18 0^{\circ} + 36 0^{\circ} n - 9 0^{\circ} + 1 0^{\circ}

2, 18

的最小公倍数:

18

2, 18

最小公倍数 (LCM)

2

质因数分解:

2

2

2

是质数，因此无法因数分解

= 2

18

质因数分解:

2 \cdot 3 \cdot 3

18

18

除以

218 = 9 \cdot 2

= 2 \cdot 9

9

除以

39 = 3 \cdot 3

= 2 \cdot 3 \cdot 3

2, 3

都是质数，因此无法进一步因数分解

= 2 \cdot 3 \cdot 3

将每个因子乘以它在

2

或

18

中出现的最多次数

= 2 \cdot 3 \cdot 3

数字相乘:

2 \cdot 3 \cdot 3 = 18

= 18

根据最小公倍数调整分式

将每个分子乘以其分母转变为最小公倍数所要乘以的同一数值

18

对于

9 0^{\circ} :

将分母和分子乘以

9

9 0^{\circ} = \frac{18 0 ^{\circ} 9}{2 \cdot 9} = 9 0^{\circ}

= - 9 0^{\circ} + 1 0^{\circ}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 18 0 ^{\circ} 9 + 18 0 ^{\circ}}{18}

同类项相加:

- 162 0^{\circ} + 18 0^{\circ} = - 144 0^{\circ}

= \frac{- 144 0 ^{\circ}}{18}

使用分式法则:

\frac{- a}{b} = - \frac{a}{b}

= - 8 0^{\circ}

约分:

2

= θ + 18 0^{\circ} + 36 0^{\circ} n - 8 0^{\circ}

= θ + 18 0^{\circ} + 36 0^{\circ} n - 8 0^{\circ}

\frac{θ}{3} = θ + 18 0^{\circ} + 36 0^{\circ} n - 8 0^{\circ}

\frac{θ}{3} = θ + 18 0^{\circ} + 36 0^{\circ} n - 8 0^{\circ}

\frac{θ}{3} = θ + 18 0^{\circ} + 36 0^{\circ} n - 8 0^{\circ}

在两边乘以

3

\frac{θ}{3} = θ + 18 0^{\circ} + 36 0^{\circ} n - 8 0^{\circ}

在两边乘以

3

\frac{θ}{3} \cdot 3 = θ \cdot 3 + 18 0^{\circ} 3 + 36 0^{\circ} n \cdot 3 - 8 0^{\circ} \cdot 3

化简

\frac{θ}{3} \cdot 3 = θ \cdot 3 + 18 0^{\circ} 3 + 36 0^{\circ} n \cdot 3 - 8 0^{\circ} \cdot 3

化简

\frac{θ}{3} \cdot 3 : θ

\frac{θ}{3} \cdot 3

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{θ \cdot 3}{3}

约分:

3

= θ

化简

θ \cdot 3 : 3 θ

θ \cdot 3

使用交换律:

θ \cdot 3 = 3 θ

3 θ

化简

18 0^{\circ} 3 : 54 0^{\circ}

18 0^{\circ} 3

使用交换律:

18 0^{\circ} 3 = 54 0^{\circ}

54 0^{\circ}

化简

36 0^{\circ} n \cdot 3 : 108 0^{\circ} n

36 0^{\circ} n \cdot 3

数字相乘:

2 \cdot 3 = 6

= 108 0^{\circ} n

化简

- 8 0^{\circ} \cdot 3 : - 24 0^{\circ}

- 8 0^{\circ} \cdot 3

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - 24 0^{\circ}

数字相乘:

4 \cdot 3 = 12

= - 24 0^{\circ}

约分:

3

= - 24 0^{\circ}

θ = 3 θ + 54 0^{\circ} + 108 0^{\circ} n - 24 0^{\circ}

θ = 3 θ + 54 0^{\circ} + 108 0^{\circ} n - 24 0^{\circ}

θ = 3 θ + 54 0^{\circ} + 108 0^{\circ} n - 24 0^{\circ}

将

3 θ

para o lado esquerdo

θ = 3 θ + 54 0^{\circ} + 108 0^{\circ} n - 24 0^{\circ}

两边减去

3 θ

θ - 3 θ = 3 θ + 54 0^{\circ} + 108 0^{\circ} n - 24 0^{\circ} - 3 θ

化简

- 2 θ = 54 0^{\circ} + 108 0^{\circ} n - 24 0^{\circ}

- 2 θ = 54 0^{\circ} + 108 0^{\circ} n - 24 0^{\circ}

两边除以

- 2

- 2 θ = 54 0^{\circ} + 108 0^{\circ} n - 24 0^{\circ}

两边除以

- 2

\frac{- 2 θ}{- 2} = \frac{54 0 ^{\circ}}{- 2} + \frac{108 0 ^{\circ} n}{- 2} - \frac{24 0 ^{\circ}}{- 2}

化简

\frac{- 2 θ}{- 2} = \frac{54 0 ^{\circ}}{- 2} + \frac{108 0 ^{\circ} n}{- 2} - \frac{24 0 ^{\circ}}{- 2}

化简

\frac{- 2 θ}{- 2} : θ

\frac{- 2 θ}{- 2}

使用分式法则:

\frac{- a}{- b} = \frac{a}{b}

= \frac{2 θ}{2}

数字相除:

\frac{2}{2} = 1

= θ

化简

\frac{54 0 ^{\circ}}{- 2} + \frac{108 0 ^{\circ} n}{- 2} - \frac{24 0 ^{\circ}}{- 2} : - \frac{90 0 ^{\circ} + 324 0 ^{\circ} n}{6}

\frac{54 0 ^{\circ}}{- 2} + \frac{108 0 ^{\circ} n}{- 2} - \frac{24 0 ^{\circ}}{- 2}

使用法则

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{54 0 ^{\circ} + 108 0 ^{\circ} n - 24 0 ^{\circ}}{- 2}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{54 0 ^{\circ} + 108 0 ^{\circ} n - 24 0 ^{\circ}}{2}

化简

54 0^{\circ} + 108 0^{\circ} n - 24 0^{\circ} : \frac{90 0 ^{\circ} + 324 0 ^{\circ} n}{3}

54 0^{\circ} + 108 0^{\circ} n - 24 0^{\circ}

将项转换为分式:

54 0^{\circ} = 54 0^{\circ}, 108 0^{\circ} n = \frac{108 0 ^{\circ} n 3}{3}

= 54 0^{\circ} + \frac{108 0 ^{\circ} n \cdot 3}{3} - 24 0^{\circ}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{54 0 ^{\circ} 3 + 108 0 ^{\circ} n \cdot 3 - 72 0 ^{\circ}}{3}

54 0^{\circ} 3 + 108 0^{\circ} n \cdot 3 - 72 0^{\circ} = 90 0^{\circ} + 324 0^{\circ} n

54 0^{\circ} 3 + 108 0^{\circ} n \cdot 3 - 72 0^{\circ}

数字相乘:

3 \cdot 3 = 9

= 162 0^{\circ} + 6 \cdot 54 0^{\circ} n - 72 0^{\circ}

数字相乘:

6 \cdot 3 = 18

= 162 0^{\circ} + 324 0^{\circ} n - 72 0^{\circ}

对同类项分组

= 162 0^{\circ} - 72 0^{\circ} + 324 0^{\circ} n

同类项相加:

162 0^{\circ} - 72 0^{\circ} = 90 0^{\circ}

= 90 0^{\circ} + 324 0^{\circ} n

= \frac{90 0 ^{\circ} + 324 0 ^{\circ} n}{3}

= - \frac{\frac{90 0 ^{\circ} + 324 0 ^{\circ} n}{3}}{2}

化简

\frac{\frac{90 0 ^{\circ} + 324 0 ^{\circ} n}{3}}{2} : \frac{90 0 ^{\circ} + 324 0 ^{\circ} n}{6}

\frac{\frac{90 0 ^{\circ} + 324 0 ^{\circ} n}{3}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{90 0 ^{\circ} + 324 0 ^{\circ} n}{3 \cdot 2}

数字相乘:

3 \cdot 2 = 6

= \frac{90 0 ^{\circ} + 324 0 ^{\circ} n}{6}

= - \frac{90 0 ^{\circ} + 324 0 ^{\circ} n}{6}

θ = - \frac{90 0 ^{\circ} + 324 0 ^{\circ} n}{6}

θ = - \frac{90 0 ^{\circ} + 324 0 ^{\circ} n}{6}

θ = - \frac{90 0 ^{\circ} + 324 0 ^{\circ} n}{6}

θ = \frac{324 0 ^{\circ} n + 90 0 ^{\circ}}{12}, θ = - \frac{90 0 ^{\circ} + 324 0 ^{\circ} n}{6}

θ = \frac{324 0 ^{\circ} n + 90 0 ^{\circ}}{12}, θ = - \frac{90 0 ^{\circ} + 324 0 ^{\circ} n}{6}

作图

流行的例子

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tan (θ) = \frac{8}{6}

2cos(x)tan(x)+tan(x)=1+2cos(x)

2 cos (x) tan (x) + tan (x) = 1 + 2 cos (x)

tan(45-x)+tan(x)=1

tan (4 5^{\circ} - x) + tan (x) = 1

tan(3B+5)=cot(2B+10)

tan (3 B + 5^{\circ}) = cot (2 B + 1 0^{\circ})