Is tan^2(a)+sin^2(a)=tan^2(a)sin^2(a) ?

The answer to whether tan^2(a)+sin^2(a)=tan^2(a)sin^2(a) is False

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prove tan^2(a)+sin^2(a)=tan^2(a)sin^2(a)

prove

tan^{2} (a) + sin^{2} (a) = tan^{2} (a) sin^{2} (a)

False

Solution steps

tan^{2} (a) + sin^{2} (a) = tan^{2} (a) sin^{2} (a)

Show that the two sides are not equal

For

tan^{2} (a) + sin^{2} (a) = tan^{2} (a) sin^{2} (a)

plug in

a = 1

tan^{2} (1) + sin^{2} (1) = 3.13359 \dots

tan^{2} (1) + sin^{2} (1)

Refine to a decimal form

= 3.13359 \dots

tan^{2} (1) sin^{2} (1) = 1.71744 \dots

tan^{2} (1) sin^{2} (1)

Refine to a decimal form

= 1.71744 \dots

The two sides are not equal

\Rightarrow False

Is tan^2(a)+sin^2(a)=tan^2(a)sin^2(a) ?
The answer to whether tan^2(a)+sin^2(a)=tan^2(a)sin^2(a) is False