tan(x)<0.7

Lösung

tan (x) < 0.7

- \frac{π}{2} + πn < x < 0.61072 \dots + πn

Intervall-Notation

(- \frac{π}{2} + πn, 0.61072 \dots + πn)

Dezimale

- 1.57079 \dots + πn < x < 0.61072 \dots + πn

Schritte zur Lösung

tan (x) < 0.7

Wenn

tan (x) < a

dann

- \frac{π}{2} + πn < x < arctan (a) + πn

- \frac{π}{2} + πn < x < arctan (0.7) + πn

Vereinfache

- \frac{π}{2} + πn < x < 0.61072 \dots + πn

sin (2 x) > 0

sin (x) \geq \frac{1}{2}

tan (θ) > 0

sin (x) > \frac{3}{2}

sin (x) cos (2 x) > 0