arcsin^2((sqrt(2))/2)

解

arcsin^{2} (\frac{2}{2})

\frac{π ^{2}}{16}

十進法表記

35.34

解答ステップ

arcsin^{2} (\frac{2}{2})

次の自明恒等式を使用する:

arcsin (\frac{2}{2}) = \frac{π}{4}

arcsin (\frac{2}{2})

x 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arcsin (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} arcsin (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ}

= \frac{π}{4}

= (\frac{π}{4})^{2}

簡素化

(\frac{π}{4})^{2} : \frac{π ^{2}}{16}

(\frac{π}{4})^{2}

指数の規則を適用する:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{π ^{2}}{4 ^{2}}

4^{2} = 16

= \frac{π ^{2}}{16}

= \frac{π ^{2}}{16}