What is the value of 0.8*4/(2pi)cos((2pi)/4*1.5+pi/2) ?

The value of 0.8*4/(2pi)cos((2pi)/4*1.5+pi/2) is -(4sqrt(2))/(5pi)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Trigonometry >

0.84/(2pi)cos((2pi)/41.5+pi/2)

Solution

0.8 \cdot \frac{4}{2 π} cos (\frac{2 π}{4} \cdot 1.5 + \frac{π}{2})

Solution

- \frac{4 2}{5 π}

Decimal

- 0.36012 \dots

Solution steps

0.8 \cdot \frac{4}{2 π} cos (\frac{2 π}{4} \cdot 1.5 + \frac{π}{2})

= \frac{4}{5} \cdot \frac{4}{2 π} cos (\frac{2 π}{4} \cdot \frac{3}{2} + \frac{π}{2})

Rewrite using trig identities:

cos (\frac{2 π}{4} \cdot \frac{3}{2} + \frac{π}{2}) = cos (\frac{3 π}{4}) cos (\frac{π}{2}) - sin (\frac{3 π}{4}) sin (\frac{π}{2})

cos (\frac{2 π}{4} \cdot \frac{3}{2} + \frac{π}{2})

Use the Angle Sum identity:

cos (s + t) = cos (s) cos (t) - sin (s) sin (t)

= cos (\frac{2 π}{4} \cdot \frac{3}{2}) cos (\frac{π}{2}) - sin (\frac{2 π}{4} \cdot \frac{3}{2}) sin (\frac{π}{2})

Simplify:

\frac{2 π}{4} \cdot \frac{3}{2} = \frac{3 π}{4}

\frac{2 π}{4} \cdot \frac{3}{2}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{2 π 3}{4 \cdot 2}

Cancel the common factor:

2

= \frac{π 3}{4}

= cos (\frac{3 π}{4}) cos (\frac{π}{2}) - sin (\frac{3 π}{4}) sin (\frac{π}{2})

= \frac{4}{5} \cdot \frac{4}{2 π} (cos (\frac{3 π}{4}) cos (\frac{π}{2}) - sin (\frac{3 π}{4}) sin (\frac{π}{2}))

\frac{4}{5} \cdot \frac{4}{2 π} (cos (\frac{3 π}{4}) cos (\frac{π}{2}) - sin (\frac{3 π}{4}) sin (\frac{π}{2})) = \frac{8 ( cos ( \frac{π}{2} ) cos ( \frac{3 π}{4} ) - sin ( \frac{π}{2} ) sin ( \frac{3 π}{4} ) )}{5 π}

\frac{4}{5} \cdot \frac{4}{2 π} (cos (\frac{3 π}{4}) cos (\frac{π}{2}) - sin (\frac{3 π}{4}) sin (\frac{π}{2}))

Multiply fractions:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{4 \cdot 4 ( cos ( \frac{3 π}{4} ) cos ( \frac{π}{2} ) - sin ( \frac{3 π}{4} ) sin ( \frac{π}{2} ) )}{5 \cdot 2 π}

Multiply the numbers:

4 \cdot 4 = 16

= \frac{16 ( cos ( \frac{π}{2} ) cos ( \frac{3 π}{4} ) - sin ( \frac{π}{2} ) sin ( \frac{3 π}{4} ) )}{5 \cdot 2 π}

Multiply the numbers:

5 \cdot 2 = 10

= \frac{16 ( cos ( \frac{π}{2} ) cos ( \frac{3 π}{4} ) - sin ( \frac{π}{2} ) sin ( \frac{3 π}{4} ) )}{10 π}

Cancel the common factor:

2

= \frac{8 ( cos ( \frac{π}{2} ) cos ( \frac{3 π}{4} ) - sin ( \frac{π}{2} ) sin ( \frac{3 π}{4} ) )}{5 π}

= \frac{8 ( cos ( \frac{π}{2} ) cos ( \frac{3 π}{4} ) - sin ( \frac{π}{2} ) sin ( \frac{3 π}{4} ) )}{5 π}

Use the following trivial identity:

cos (\frac{π}{2}) = 0

cos (\frac{π}{2})

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 0

Use the following trivial identity:

cos (\frac{3 π}{4}) = - \frac{2}{2}

cos (\frac{3 π}{4})

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= - \frac{2}{2}

Use the following trivial identity:

sin (\frac{π}{2}) = 1

sin (\frac{π}{2})

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 1

Use the following trivial identity:

sin (\frac{3 π}{4}) = \frac{2}{2}

sin (\frac{3 π}{4})

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{2}{2}

= \frac{8 ( 0 \cdot ( - \frac{2}{2} ) - 1 \cdot \frac{2}{2} )}{5 π}

Simplify

\frac{8 ( 0 \cdot ( - \frac{2}{2} ) - 1 \cdot \frac{2}{2} )}{5 π} : - \frac{4 2}{5 π}

\frac{8 ( 0 \cdot ( - \frac{2}{2} ) - 1 \cdot \frac{2}{2} )}{5 π}

Remove parentheses:

(- a) = - a

= \frac{8 ( - 0 \cdot \frac{2}{2} - 1 \cdot \frac{2}{2} )}{5 π}

8 (- 0 \cdot \frac{2}{2} - 1 \cdot \frac{2}{2}) = - 8 \cdot \frac{2}{2}

8 (- 0 \cdot \frac{2}{2} - 1 \cdot \frac{2}{2})

Add similar elements:

- 0 \cdot \frac{2}{2} - 1 \cdot \frac{2}{2} = - \frac{2}{2}

= 8 (- \frac{2}{2})

Remove parentheses:

(- a) = - a

= - 8 \cdot \frac{2}{2}

= \frac{- 8 \cdot \frac{2}{2}}{5 π}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{8 \cdot \frac{2}{2}}{5 π}

Multiply

8 \cdot \frac{2}{2} : 42

8 \cdot \frac{2}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 \cdot 8}{2}

Divide the numbers:

\frac{8}{2} = 4

= 42

= - \frac{4 2}{5 π}

= - \frac{4 2}{5 π}

Popular Examples

sec^2(-0.01)

arccos(-(sqrt(2))/2)+arctan((sqrt(3))/3)

6sin(2(pi/2))

sin(90.1)

7*tan(36)

Frequently Asked Questions (FAQ)

What is the value of 0.8*4/(2pi)cos((2pi)/4*1.5+pi/2) ?
The value of 0.8*4/(2pi)cos((2pi)/4*1.5+pi/2) is -(4sqrt(2))/(5pi)