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人気のある三角関数 >

3cos(3x)=2cos(x)

解

3 cos (3 x) = 2 cos (x)

解

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn, x = 2.84874 \dots + 2 πn, x = - 2.84874 \dots + 2 πn, x = 0.29284 \dots + 2 πn, x = 2 π - 0.29284 \dots + 2 πn

+1

度

x = 9 0^{\circ} + 36 0^{\circ} n, x = 27 0^{\circ} + 36 0^{\circ} n, x = 163.22134 \dots^{\circ} + 36 0^{\circ} n, x = - 163.22134 \dots^{\circ} + 36 0^{\circ} n, x = 16.77865 \dots^{\circ} + 36 0^{\circ} n, x = 343.22134 \dots^{\circ} + 36 0^{\circ} n

解答ステップ

3 cos (3 x) = 2 cos (x)

両辺から

2 cos (x)

を引く

3 cos (3 x) - 2 cos (x) = 0

三角関数の公式を使用して書き換える

- 2 cos (x) + 3 cos (3 x)

cos (3 x) = 4 cos^{3} (x) - 3 cos (x)

cos (3 x)

三角関数の公式を使用して書き換える

cos (3 x)

書き換え

= cos (2 x + x)

角の和の公式を使用する:

cos (s + t) = cos (s) cos (t) - sin (s) sin (t)

= cos (2 x) cos (x) - sin (2 x) sin (x)

2倍角の公式を使用:

sin (2 x) = 2 sin (x) cos (x)

= cos (2 x) cos (x) - 2 sin (x) cos (x) sin (x)

簡素化

cos (2 x) cos (x) - 2 sin (x) cos (x) sin (x) : cos (x) cos (2 x) - 2 sin^{2} (x) cos (x)

cos (2 x) cos (x) - 2 sin (x) cos (x) sin (x)

2 sin (x) cos (x) sin (x) = 2 sin^{2} (x) cos (x)

2 sin (x) cos (x) sin (x)

指数の規則を適用する:

a^{b} \cdot a^{c} = a^{b + c}

sin (x) sin (x) = sin^{1 + 1} (x)

= 2 cos (x) sin^{1 + 1} (x)

数を足す:

1 + 1 = 2

= 2 cos (x) sin^{2} (x)

= cos (x) cos (2 x) - 2 sin^{2} (x) cos (x)

= cos (x) cos (2 x) - 2 sin^{2} (x) cos (x)

= cos (x) cos (2 x) - 2 sin^{2} (x) cos (x)

2倍角の公式を使用:

cos (2 x) = 2 cos^{2} (x) - 1

= (2 cos^{2} (x) - 1) cos (x) - 2 sin^{2} (x) cos (x)

ピタゴラスの公式を使用する:

cos^{2} (x) + sin^{2} (x) = 1

sin^{2} (x) = 1 - cos^{2} (x)

= (2 cos^{2} (x) - 1) cos (x) - 2 (1 - cos^{2} (x)) cos (x)

拡張

(2 cos^{2} (x) - 1) cos (x) - 2 (1 - cos^{2} (x)) cos (x) : 4 cos^{3} (x) - 3 cos (x)

(2 cos^{2} (x) - 1) cos (x) - 2 (1 - cos^{2} (x)) cos (x)

= cos (x) (2 cos^{2} (x) - 1) - 2 cos (x) (1 - cos^{2} (x))

拡張

cos (x) (2 cos^{2} (x) - 1) : 2 cos^{3} (x) - cos (x)

cos (x) (2 cos^{2} (x) - 1)

分配法則を適用する:

a (b - c) = ab - a c

a = cos (x), b = 2 cos^{2} (x), c = 1

= cos (x) 2 cos^{2} (x) - cos (x) 1

= 2 cos^{2} (x) cos (x) - 1 cos (x)

簡素化

2 cos^{2} (x) cos (x) - 1 \cdot cos (x) : 2 cos^{3} (x) - cos (x)

2 cos^{2} (x) cos (x) - 1 cos (x)

2 cos^{2} (x) cos (x) = 2 cos^{3} (x)

2 cos^{2} (x) cos (x)

指数の規則を適用する:

a^{b} \cdot a^{c} = a^{b + c}

cos^{2} (x) cos (x) = cos^{2 + 1} (x)

= 2 cos^{2 + 1} (x)

数を足す:

2 + 1 = 3

= 2 cos^{3} (x)

1 \cdot cos (x) = cos (x)

1 cos (x)

乗算:

1 \cdot cos (x) = cos (x)

= cos (x)

= 2 cos^{3} (x) - cos (x)

= 2 cos^{3} (x) - cos (x)

= 2 cos^{3} (x) - cos (x) - 2 (1 - cos^{2} (x)) cos (x)

拡張

- 2 cos (x) (1 - cos^{2} (x)) : - 2 cos (x) + 2 cos^{3} (x)

- 2 cos (x) (1 - cos^{2} (x))

分配法則を適用する:

a (b - c) = ab - a c

a = - 2 cos (x), b = 1, c = cos^{2} (x)

= - 2 cos (x) 1 - (- 2 cos (x)) cos^{2} (x)

マイナス・プラスの規則を適用する

- (- a) = a

= - 2 \cdot 1 cos (x) + 2 cos^{2} (x) cos (x)

簡素化

- 2 \cdot 1 \cdot cos (x) + 2 cos^{2} (x) cos (x) : - 2 cos (x) + 2 cos^{3} (x)

- 2 \cdot 1 cos (x) + 2 cos^{2} (x) cos (x)

2 \cdot 1 \cdot cos (x) = 2 cos (x)

2 \cdot 1 cos (x)

数を乗じる:

2 \cdot 1 = 2

= 2 cos (x)

2 cos^{2} (x) cos (x) = 2 cos^{3} (x)

2 cos^{2} (x) cos (x)

指数の規則を適用する:

a^{b} \cdot a^{c} = a^{b + c}

cos^{2} (x) cos (x) = cos^{2 + 1} (x)

= 2 cos^{2 + 1} (x)

数を足す:

2 + 1 = 3

= 2 cos^{3} (x)

= - 2 cos (x) + 2 cos^{3} (x)

= - 2 cos (x) + 2 cos^{3} (x)

= 2 cos^{3} (x) - cos (x) - 2 cos (x) + 2 cos^{3} (x)

簡素化

2 cos^{3} (x) - cos (x) - 2 cos (x) + 2 cos^{3} (x) : 4 cos^{3} (x) - 3 cos (x)

2 cos^{3} (x) - cos (x) - 2 cos (x) + 2 cos^{3} (x)

条件のようなグループ

= 2 cos^{3} (x) + 2 cos^{3} (x) - cos (x) - 2 cos (x)

類似した元を足す:

2 cos^{3} (x) + 2 cos^{3} (x) = 4 cos^{3} (x)

= 4 cos^{3} (x) - cos (x) - 2 cos (x)

類似した元を足す:

- cos (x) - 2 cos (x) = - 3 cos (x)

= 4 cos^{3} (x) - 3 cos (x)

= 4 cos^{3} (x) - 3 cos (x)

= 4 cos^{3} (x) - 3 cos (x)

= - 2 cos (x) + 3 (4 cos^{3} (x) - 3 cos (x))

簡素化

- 2 cos (x) + 3 (4 cos^{3} (x) - 3 cos (x)) : - 11 cos (x) + 12 cos^{3} (x)

- 2 cos (x) + 3 (4 cos^{3} (x) - 3 cos (x))

拡張

3 (4 cos^{3} (x) - 3 cos (x)) : 12 cos^{3} (x) - 9 cos (x)

3 (4 cos^{3} (x) - 3 cos (x))

分配法則を適用する:

a (b - c) = ab - a c

a = 3, b = 4 cos^{3} (x), c = 3 cos (x)

= 3 \cdot 4 cos^{3} (x) - 3 \cdot 3 cos (x)

簡素化

3 \cdot 4 cos^{3} (x) - 3 \cdot 3 cos (x) : 12 cos^{3} (x) - 9 cos (x)

3 \cdot 4 cos^{3} (x) - 3 \cdot 3 cos (x)

数を乗じる:

3 \cdot 4 = 12

= 12 cos^{3} (x) - 3 \cdot 3 cos (x)

数を乗じる:

3 \cdot 3 = 9

= 12 cos^{3} (x) - 9 cos (x)

= 12 cos^{3} (x) - 9 cos (x)

= - 2 cos (x) + 12 cos^{3} (x) - 9 cos (x)

類似した元を足す:

- 2 cos (x) - 9 cos (x) = - 11 cos (x)

= - 11 cos (x) + 12 cos^{3} (x)

= - 11 cos (x) + 12 cos^{3} (x)

- 11 cos (x) + 12 cos^{3} (x) = 0

置換で解く

- 11 cos (x) + 12 cos^{3} (x) = 0

仮定:

cos (x) = u

- 11 u + 12 u^{3} = 0

- 11 u + 12 u^{3} = 0 : u = 0, u = - \frac{33}{6}, u = \frac{33}{6}

- 11 u + 12 u^{3} = 0

因数

- 11 u + 12 u^{3} : u (23 u + 11) (23 u - 11)

- 11 u + 12 u^{3}

共通項をくくり出す

u : u (12 u^{2} - 11)

12 u^{3} - 11 u

指数の規則を適用する:

a^{b + c} = a^{b} a^{c}

u^{3} = u^{2} u

= 12 u^{2} u - 11 u

共通項をくくり出す

u

= u (12 u^{2} - 11)

= u (12 u^{2} - 11)

因数

12 u^{2} - 11 : (12 u + 11) (12 u - 11)

12 u^{2} - 11

12 u^{2} - 11

を書き換え

(12 u)^{2} - (11)^{2}

12 u^{2} - 11

累乗根の規則を適用する:

a = (a)^{2}

12 = (12)^{2}

= (12)^{2} u^{2} - 11

累乗根の規則を適用する:

a = (a)^{2}

11 = (11)^{2}

= (12)^{2} u^{2} - (11)^{2}

指数の規則を適用する:

a^{m} b^{m} = (ab)^{m}

(12)^{2} u^{2} = (12 u)^{2}

= (12 u)^{2} - (11)^{2}

= (12 u)^{2} - (11)^{2}

2乗の差の公式を適用する:

x^{2} - y^{2} = (x + y) (x - y)

(12 u)^{2} - (11)^{2} = (12 u + 11) (12 u - 11)

= (12 u + 11) (12 u - 11)

= u (12 u + 11) (12 u - 11)

改良

= u (23 u + 11) (23 u - 11)

u (23 u + 11) (23 u - 11) = 0

零因子の原則を使用:

ab = 0

ならば

a = 0

または

b = 0

u = 0 or 23 u + 11 = 0 or 23 u - 11 = 0

解く

23 u + 11 = 0 : u = - \frac{33}{6}

23 u + 11 = 0

11

を右側に移動します

23 u + 11 = 0

両辺から

11

を引く

23 u + 11 - 11 = 0 - 11

簡素化

23 u = - 11

23 u = - 11

以下で両辺を割る

23

23 u = - 11

以下で両辺を割る

23

\frac{2 3 u}{2 3} = \frac{- 11}{2 3}

簡素化

\frac{2 3 u}{2 3} = \frac{- 11}{2 3}

簡素化

\frac{2 3 u}{2 3} : u

\frac{2 3 u}{2 3}

数を割る:

\frac{2}{2} = 1

= \frac{3 u}{3}

共通因数を約分する:

3

= u

簡素化

\frac{- 11}{2 3} : - \frac{33}{6}

\frac{- 11}{2 3}

分数の規則を適用する:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{11}{2 3}

有理化する

- \frac{11}{2 3} : - \frac{33}{6}

- \frac{11}{2 3}

共役で乗じる

\frac{3}{3}

= - \frac{11 3}{2 3 3}

113 = 33

113

累乗根の規則を適用する:

a b = a \cdot b

113 = 11 \cdot 3

= 11 \cdot 3

数を乗じる:

11 \cdot 3 = 33

= 33

233 = 6

233

累乗根の規則を適用する:

a a = a

33 = 3

= 2 \cdot 3

数を乗じる:

2 \cdot 3 = 6

= 6

= - \frac{33}{6}

= - \frac{33}{6}

u = - \frac{33}{6}

u = - \frac{33}{6}

u = - \frac{33}{6}

解く

23 u - 11 = 0 : u = \frac{33}{6}

23 u - 11 = 0

11

を右側に移動します

23 u - 11 = 0

両辺に

11

を足す

23 u - 11 + 11 = 0 + 11

簡素化

23 u = 11

23 u = 11

以下で両辺を割る

23

23 u = 11

以下で両辺を割る

23

\frac{2 3 u}{2 3} = \frac{11}{2 3}

簡素化

\frac{2 3 u}{2 3} = \frac{11}{2 3}

簡素化

\frac{2 3 u}{2 3} : u

\frac{2 3 u}{2 3}

数を割る:

\frac{2}{2} = 1

= \frac{3 u}{3}

共通因数を約分する:

3

= u

簡素化

\frac{11}{2 3} : \frac{33}{6}

\frac{11}{2 3}

共役で乗じる

\frac{3}{3}

= \frac{11 3}{2 3 3}

113 = 33

113

累乗根の規則を適用する:

a b = a \cdot b

113 = 11 \cdot 3

= 11 \cdot 3

数を乗じる:

11 \cdot 3 = 33

= 33

233 = 6

233

累乗根の規則を適用する:

a a = a

33 = 3

= 2 \cdot 3

数を乗じる:

2 \cdot 3 = 6

= 6

= \frac{33}{6}

u = \frac{33}{6}

u = \frac{33}{6}

u = \frac{33}{6}

解答は

u = 0, u = - \frac{33}{6}, u = \frac{33}{6}

代用を戻す

u = cos (x)

cos (x) = 0, cos (x) = - \frac{33}{6}, cos (x) = \frac{33}{6}

cos (x) = 0, cos (x) = - \frac{33}{6}, cos (x) = \frac{33}{6}

cos (x) = 0 : x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

cos (x) = 0

以下の一般解

cos (x) = 0

cos (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

cos (x) = - \frac{33}{6} : x = arccos (- \frac{33}{6}) + 2 πn, x = - arccos (- \frac{33}{6}) + 2 πn

cos (x) = - \frac{33}{6}

三角関数の逆数プロパティを適用する

cos (x) = - \frac{33}{6}

以下の一般解

cos (x) = - \frac{33}{6}

cos (x) = - a \Rightarrow x = arccos (- a) + 2 πn, x = - arccos (- a) + 2 πn

x = arccos (- \frac{33}{6}) + 2 πn, x = - arccos (- \frac{33}{6}) + 2 πn

x = arccos (- \frac{33}{6}) + 2 πn, x = - arccos (- \frac{33}{6}) + 2 πn

cos (x) = \frac{33}{6} : x = arccos (\frac{33}{6}) + 2 πn, x = 2 π - arccos (\frac{33}{6}) + 2 πn

cos (x) = \frac{33}{6}

三角関数の逆数プロパティを適用する

cos (x) = \frac{33}{6}

以下の一般解

cos (x) = \frac{33}{6}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (\frac{33}{6}) + 2 πn, x = 2 π - arccos (\frac{33}{6}) + 2 πn

x = arccos (\frac{33}{6}) + 2 πn, x = 2 π - arccos (\frac{33}{6}) + 2 πn

すべての解を組み合わせる

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn, x = arccos (- \frac{33}{6}) + 2 πn, x = - arccos (- \frac{33}{6}) + 2 πn, x = arccos (\frac{33}{6}) + 2 πn, x = 2 π - arccos (\frac{33}{6}) + 2 πn

10進法形式で解を証明する

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn, x = 2.84874 \dots + 2 πn, x = - 2.84874 \dots + 2 πn, x = 0.29284 \dots + 2 πn, x = 2 π - 0.29284 \dots + 2 πn

グラフ

人気の例

4cos^2(x)+4sin(x)-1=0

4 cos^{2} (x) + 4 sin (x) - 1 = 0

sin (x - 1) = 0

csc (θ) = - 0.5

cot(2t+5)=tan(3t-15)

cot (2 t + 5) = tan (3 t - 15)

2cos(x)-4sin(x)cos(x)=0

2 cos (x) - 4 sin (x) cos (x) = 0