What is the general solution for cos(θ)= 12/20 ?

The general solution for cos(θ)= 12/20 is θ=0.92729…+2pin,θ=2pi-0.92729…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

cos(θ)= 12/20

cos (θ) = \frac{12}{20}

θ = 0.92729 \dots + 2 πn, θ = 2 π - 0.92729 \dots + 2 πn

Degrees

θ = 53.13010 \dots^{\circ} + 36 0^{\circ} n, θ = 306.86989 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (θ) = \frac{12}{20}

Cancel the common factor:

4

cos (θ) = \frac{3}{5}

Apply trig inverse properties

cos (θ) = \frac{3}{5}

General solutions for

cos (θ) = \frac{3}{5}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{3}{5}) + 2 πn, θ = 2 π - arccos (\frac{3}{5}) + 2 πn

θ = arccos (\frac{3}{5}) + 2 πn, θ = 2 π - arccos (\frac{3}{5}) + 2 πn

Show solutions in decimal form

θ = 0.92729 \dots + 2 πn, θ = 2 π - 0.92729 \dots + 2 πn

What is the general solution for cos(θ)= 12/20 ?
The general solution for cos(θ)= 12/20 is θ=0.92729…+2pin,θ=2pi-0.92729…+2pin