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受欢迎的三角函数 >

cos(2x)cos(x)-sin(2x)sin(x)=(sqrt(2))/2

解答

cos (2 x) cos (x) - sin (2 x) sin (x) = \frac{2}{2}

解答

x = \frac{π}{12} + \frac{2 πn}{3}, x = \frac{7 π}{12} + \frac{2 πn}{3}

+1

度数

x = 1 5^{\circ} + 12 0^{\circ} n, x = 10 5^{\circ} + 12 0^{\circ} n

求解步骤

cos (2 x) cos (x) - sin (2 x) sin (x) = \frac{2}{2}

使用三角恒等式改写

cos (2 x) cos (x) - sin (2 x) sin (x)

使用角和恒等式:

cos (s) cos (t) - sin (s) sin (t) = cos (s + t)

= cos (2 x + x)

cos (2 x + x) = \frac{2}{2}

cos (2 x + x) = \frac{2}{2}

的通解

cos (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

2 x + x = \frac{π}{4} + 2 πn, 2 x + x = \frac{7 π}{4} + 2 πn

2 x + x = \frac{π}{4} + 2 πn, 2 x + x = \frac{7 π}{4} + 2 πn

解

2 x + x = \frac{π}{4} + 2 πn : x = \frac{π}{12} + \frac{2 πn}{3}

2 x + x = \frac{π}{4} + 2 πn

同类项相加:

2 x + x = 3 x

3 x = \frac{π}{4} + 2 πn

两边除以

3

3 x = \frac{π}{4} + 2 πn

两边除以

3

\frac{3 x}{3} = \frac{\frac{π}{4}}{3} + \frac{2 πn}{3}

化简

\frac{3 x}{3} = \frac{\frac{π}{4}}{3} + \frac{2 πn}{3}

化简

\frac{3 x}{3} : x

\frac{3 x}{3}

数字相除:

\frac{3}{3} = 1

= x

化简

\frac{\frac{π}{4}}{3} + \frac{2 πn}{3} : \frac{π}{12} + \frac{2 πn}{3}

\frac{\frac{π}{4}}{3} + \frac{2 πn}{3}

\frac{\frac{π}{4}}{3} = \frac{π}{12}

\frac{\frac{π}{4}}{3}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{4 \cdot 3}

数字相乘:

4 \cdot 3 = 12

= \frac{π}{12}

= \frac{π}{12} + \frac{2 πn}{3}

x = \frac{π}{12} + \frac{2 πn}{3}

x = \frac{π}{12} + \frac{2 πn}{3}

x = \frac{π}{12} + \frac{2 πn}{3}

解

2 x + x = \frac{7 π}{4} + 2 πn : x = \frac{7 π}{12} + \frac{2 πn}{3}

2 x + x = \frac{7 π}{4} + 2 πn

同类项相加:

2 x + x = 3 x

3 x = \frac{7 π}{4} + 2 πn

两边除以

3

3 x = \frac{7 π}{4} + 2 πn

两边除以

3

\frac{3 x}{3} = \frac{\frac{7 π}{4}}{3} + \frac{2 πn}{3}

化简

\frac{3 x}{3} = \frac{\frac{7 π}{4}}{3} + \frac{2 πn}{3}

化简

\frac{3 x}{3} : x

\frac{3 x}{3}

数字相除:

\frac{3}{3} = 1

= x

化简

\frac{\frac{7 π}{4}}{3} + \frac{2 πn}{3} : \frac{7 π}{12} + \frac{2 πn}{3}

\frac{\frac{7 π}{4}}{3} + \frac{2 πn}{3}

\frac{\frac{7 π}{4}}{3} = \frac{7 π}{12}

\frac{\frac{7 π}{4}}{3}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{7 π}{4 \cdot 3}

数字相乘:

4 \cdot 3 = 12

= \frac{7 π}{12}

= \frac{7 π}{12} + \frac{2 πn}{3}

x = \frac{7 π}{12} + \frac{2 πn}{3}

x = \frac{7 π}{12} + \frac{2 πn}{3}

x = \frac{7 π}{12} + \frac{2 πn}{3}

x = \frac{π}{12} + \frac{2 πn}{3}, x = \frac{7 π}{12} + \frac{2 πn}{3}

作图

流行的例子

cos(x)tan(x)=sin(2x)

cos (x) tan (x) = sin (2 x)

250sin(75)=393.19sin(45-θ)

250 sin (7 5^{\circ}) = 393.19 sin (4 5^{\circ} - θ)

tan(θ)= 6/(6.71)

tan (θ) = \frac{6}{6.71}

sin (2 θ) = 0.5

cos (\frac{π}{2} + x) = 0