cos(θ)= 10/15

Lösung

cos (θ) = \frac{10}{15}

θ = 0.84106 \dots + 2 πn, θ = 2 π - 0.84106 \dots + 2 πn

Grad

θ = 48.18968 \dots^{\circ} + 36 0^{\circ} n, θ = 311.81031 \dots^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

cos (θ) = \frac{10}{15}

Streiche die gemeinsamen Faktoren:

5

cos (θ) = \frac{2}{3}

Wende die Eigenschaften der Trigonometrie an

cos (θ) = \frac{2}{3}

Allgemeine Lösung für

cos (θ) = \frac{2}{3}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{2}{3}) + 2 πn, θ = 2 π - arccos (\frac{2}{3}) + 2 πn

θ = arccos (\frac{2}{3}) + 2 πn, θ = 2 π - arccos (\frac{2}{3}) + 2 πn

Zeige Lösungen in Dezimalform

θ = 0.84106 \dots + 2 πn, θ = 2 π - 0.84106 \dots + 2 πn

sin (θ) = \frac{40}{60}

10 = 3.44 sin (0.51 t + 4.11) + 9.48

2 cot^{2} (z) + 5 = 7 csc (z)

sin^{2} (x) = 6

sin^{2} (φ) + cos^{2} (φ) = 2