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Popular Trigonometry >

sin^5(3x^2+2)=0.35

  • Pre Algebra
  • Algebra
  • Pre Calculus
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Solution

sin5(3x2+2)=0.35

Solution

x=30.94519…+2πn−2​​,x=−30.94519…+2πn−2​​,x=3π−0.94519…+2πn−2​​,x=−3π−0.94519…+2πn−2​​
+1
Degrees
x=0∘+75.63899…∘n,x=0∘−75.63899…∘n,x=0∘+84.20452…∘n,x=0∘−84.20452…∘n
Solution steps
sin5(3x2+2)=0.35
For xn=f(a), n is odd, the solution is x=nf(a)​
sin(3x2+2)=50.35​
Apply trig inverse properties
sin(3x2+2)=50.35​
General solutions for sin(3x2+2)=50.35​sin(x)=a⇒x=arcsin(a)+2πn,x=π−arcsin(a)+2πn3x2+2=arcsin(50.35​)+2πn,3x2+2=π−arcsin(50.35​)+2πn
3x2+2=arcsin(50.35​)+2πn,3x2+2=π−arcsin(50.35​)+2πn
Solve 3x2+2=arcsin(50.35​)+2πn:x=3arcsin(50.35​)+2πn−2​​,x=−3arcsin(50.35​)+2πn−2​​
3x2+2=arcsin(50.35​)+2πn
Move 2to the right side
3x2+2=arcsin(50.35​)+2πn
Subtract 2 from both sides3x2+2−2=arcsin(50.35​)+2πn−2
Simplify3x2=arcsin(50.35​)+2πn−2
3x2=arcsin(50.35​)+2πn−2
Divide both sides by 3
3x2=arcsin(50.35​)+2πn−2
Divide both sides by 333x2​=3arcsin(50.35​)​+32πn​−32​
Simplifyx2=3arcsin(50.35​)​+32πn​−32​
x2=3arcsin(50.35​)​+32πn​−32​
For x2=f(a) the solutions are x=f(a)​,−f(a)​
x=3arcsin(50.35​)​+32πn​−32​​,x=−3arcsin(50.35​)​+32πn​−32​​
Simplify 3arcsin(50.35​)​+32πn​−32​​:3arcsin(50.35​)+2πn−2​​
3arcsin(50.35​)​+32πn​−32​​
Combine the fractions 3arcsin(50.35​)​+32πn​−32​:3arcsin(50.35​)+2πn−2​
Apply rule ca​±cb​=ca±b​=3arcsin(50.35​)+2πn−2​
=3arcsin(50.35​)+2πn−2​​
Simplify −3arcsin(50.35​)​+32πn​−32​​:−3arcsin(50.35​)+2πn−2​​
−3arcsin(50.35​)​+32πn​−32​​
Combine the fractions 3arcsin(50.35​)​+32πn​−32​:3arcsin(50.35​)+2πn−2​
Apply rule ca​±cb​=ca±b​=3arcsin(50.35​)+2πn−2​
=−32πn+arcsin(50.35​)−2​​
=−3arcsin(50.35​)+2πn−2​​
x=3arcsin(50.35​)+2πn−2​​,x=−3arcsin(50.35​)+2πn−2​​
Solve 3x2+2=π−arcsin(50.35​)+2πn:x=3π−arcsin(50.35​)+2πn−2​​,x=−3π−arcsin(50.35​)+2πn−2​​
3x2+2=π−arcsin(50.35​)+2πn
Move 2to the right side
3x2+2=π−arcsin(50.35​)+2πn
Subtract 2 from both sides3x2+2−2=π−arcsin(50.35​)+2πn−2
Simplify3x2=π−arcsin(50.35​)+2πn−2
3x2=π−arcsin(50.35​)+2πn−2
Divide both sides by 3
3x2=π−arcsin(50.35​)+2πn−2
Divide both sides by 333x2​=3π​−3arcsin(50.35​)​+32πn​−32​
Simplifyx2=3π​−3arcsin(50.35​)​+32πn​−32​
x2=3π​−3arcsin(50.35​)​+32πn​−32​
For x2=f(a) the solutions are x=f(a)​,−f(a)​
x=3π​−3arcsin(50.35​)​+32πn​−32​​,x=−3π​−3arcsin(50.35​)​+32πn​−32​​
Simplify 3π​−3arcsin(50.35​)​+32πn​−32​​:3π−arcsin(50.35​)+2πn−2​​
3π​−3arcsin(50.35​)​+32πn​−32​​
Combine the fractions 3π​−3arcsin(50.35​)​+32πn​−32​:3π−arcsin(50.35​)+2πn−2​
Apply rule ca​±cb​=ca±b​=3π−arcsin(50.35​)+2πn−2​
=3π−arcsin(50.35​)+2πn−2​​
Simplify −3π​−3arcsin(50.35​)​+32πn​−32​​:−3π−arcsin(50.35​)+2πn−2​​
−3π​−3arcsin(50.35​)​+32πn​−32​​
Combine the fractions 3π​−3arcsin(50.35​)​+32πn​−32​:3π−arcsin(50.35​)+2πn−2​
Apply rule ca​±cb​=ca±b​=3π−arcsin(50.35​)+2πn−2​
=−3π+2πn−2−arcsin(50.35​)​​
=−3π−arcsin(50.35​)+2πn−2​​
x=3π−arcsin(50.35​)+2πn−2​​,x=−3π−arcsin(50.35​)+2πn−2​​
x=3arcsin(50.35​)+2πn−2​​,x=−3arcsin(50.35​)+2πn−2​​,x=3π−arcsin(50.35​)+2πn−2​​,x=−3π−arcsin(50.35​)+2πn−2​​
Show solutions in decimal formx=30.94519…+2πn−2​​,x=−30.94519…+2πn−2​​,x=3π−0.94519…+2πn−2​​,x=−3π−0.94519…+2πn−2​​

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