English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

solvefor x,cos^2(x)=0.5

Lösung

löse nach

x, cos^{2} (x) = 0.5

x = 0.78539 \dots + 2 πn, x = 2 π - 0.78539 \dots + 2 πn, x = 2.35619 \dots + 2 πn, x = - 2.35619 \dots + 2 πn

Grad

x = 4 5^{\circ} + 36 0^{\circ} n, x = 31 5^{\circ} + 36 0^{\circ} n, x = 13 5^{\circ} + 36 0^{\circ} n, x = - 13 5^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

cos^{2} (x) = 0.5

Löse mit Substitution

cos^{2} (x) = 0.5

Angenommen:

cos (x) = u

u^{2} = 0.5

u^{2} = 0.5 : u = 0.5, u = - 0.5

u^{2} = 0.5

Für

x^{2} = f (a)

sind die Lösungen

x = f (a), - f (a)

u = 0.5, u = - 0.5

Setze in

u = cos (x)

ein

cos (x) = 0.5, cos (x) = - 0.5

cos (x) = 0.5, cos (x) = - 0.5

cos (x) = 0.5 : x = arccos (0.5) + 2 πn, x = 2 π - arccos (0.5) + 2 πn

cos (x) = 0.5

Wende die Eigenschaften der Trigonometrie an

cos (x) = 0.5

Allgemeine Lösung für

cos (x) = 0.5

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (0.5) + 2 πn, x = 2 π - arccos (0.5) + 2 πn

x = arccos (0.5) + 2 πn, x = 2 π - arccos (0.5) + 2 πn

cos (x) = - 0.5 : x = arccos (- 0.5) + 2 πn, x = - arccos (- 0.5) + 2 πn

cos (x) = - 0.5

Wende die Eigenschaften der Trigonometrie an

cos (x) = - 0.5

Allgemeine Lösung für

cos (x) = - 0.5

cos (x) = - a \Rightarrow x = arccos (- a) + 2 πn, x = - arccos (- a) + 2 πn

x = arccos (- 0.5) + 2 πn, x = - arccos (- 0.5) + 2 πn

x = arccos (- 0.5) + 2 πn, x = - arccos (- 0.5) + 2 πn

Kombiniere alle Lösungen

x = arccos (0.5) + 2 πn, x = 2 π - arccos (0.5) + 2 πn, x = arccos (- 0.5) + 2 πn, x = - arccos (- 0.5) + 2 πn

Zeige Lösungen in Dezimalform

x = 0.78539 \dots + 2 πn, x = 2 π - 0.78539 \dots + 2 πn, x = 2.35619 \dots + 2 πn, x = - 2.35619 \dots + 2 πn

sin (x) = 0.24, 0 \leq x < 2 π

sec^{2} (θ) cot (θ) = 8

4 + 5 sin (x) = 1

120 = 23 sin (\frac{π}{6} (x)) + 107

4 sin (3 θ) = 2