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受欢迎的三角函数 >

2=2-picos(t)

解答

2 = 2 - π cos (t)

解答

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

+1

度数

t = 9 0^{\circ} + 36 0^{\circ} n, t = 27 0^{\circ} + 36 0^{\circ} n

求解步骤

2 = 2 - π cos (t)

交换两边

2 - π cos (t) = 2

两边减去

2

2 - π cos (t) - 2 = 2 - 2

化简

- π cos (t) = 0

两边除以

- π

- π cos (t) = 0

两边除以

- π

\frac{- π cos ( t )}{- π} = \frac{0}{- π}

化简

cos (t) = 0

cos (t) = 0

cos (t) = 0

的通解

cos (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

作图

流行的例子

solvefor a,45=arctanh(a/b)

so l v e f or a, 45 = arctanh (\frac{a}{b})

solvefor x,sec(x)=3

so l v e f or x, sec (x) = 3

cot(θ-30)= 1/(sqrt(3))

cot (θ - 3 0^{\circ}) = \frac{1}{3}

(cot(x)-sqrt(3))(csc(x)+2)=0

(cot (x) - 3) (csc (x) + 2) = 0

sin(x)= 7/(9.4)

sin (x) = \frac{7}{9.4}