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受欢迎的三角函数 >

sin(B)= 1/(sqrt(3))

解答

sin (B) = \frac{1}{3}

解答

B = 0.61547 \dots + 2 πn, B = π - 0.61547 \dots + 2 πn

+1

弧度

B = 0.61547 \dots + 6.28318 \dots n, B = π - 0.61547 \dots + 6.28318 \dots n

求解步骤

sin (B) = \frac{1}{3}

化简

\frac{1}{3} : \frac{3}{3}

\frac{1}{3}

乘以共轭根式

\frac{3}{3}

= \frac{1 \cdot 3}{3 3}

1 \cdot 3 = 3

33 = 3

33

使用根式运算法则:

a a = a

33 = 3

= 3

= \frac{3}{3}

sin (B) = \frac{3}{3}

使用反三角函数性质

sin (B) = \frac{3}{3}

sin (B) = \frac{3}{3}

的通解

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

B = arcsin (\frac{3}{3}) + 2 πn, B = π - arcsin (\frac{3}{3}) + 2 πn

B = arcsin (\frac{3}{3}) + 2 πn, B = π - arcsin (\frac{3}{3}) + 2 πn

以小数形式表示解

B = 0.61547 \dots + 2 πn, B = π - 0.61547 \dots + 2 πn

作图

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