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受欢迎的三角函数 >

4cos(x-1)=0

解答

4 cos (x - 1) = 0

解答

x = \frac{π}{2} + 2 πn + 1, x = \frac{3 π}{2} + 2 πn + 1

+1

度数

x = 147.29577 \dots^{\circ} + 36 0^{\circ} n, x = 327.29577 \dots^{\circ} + 36 0^{\circ} n

求解步骤

4 cos (x - 1) = 0

两边除以

4

4 cos (x - 1) = 0

两边除以

4

\frac{4 cos ( x - 1 )}{4} = \frac{0}{4}

化简

cos (x - 1) = 0

cos (x - 1) = 0

cos (x - 1) = 0

的通解

cos (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x - 1 = \frac{π}{2} + 2 πn, x - 1 = \frac{3 π}{2} + 2 πn

x - 1 = \frac{π}{2} + 2 πn, x - 1 = \frac{3 π}{2} + 2 πn

解

x - 1 = \frac{π}{2} + 2 πn : x = \frac{π}{2} + 2 πn + 1

x - 1 = \frac{π}{2} + 2 πn

将

1

到右边

x - 1 = \frac{π}{2} + 2 πn

两边加上

1

x - 1 + 1 = \frac{π}{2} + 2 πn + 1

化简

x = \frac{π}{2} + 2 πn + 1

x = \frac{π}{2} + 2 πn + 1

解

x - 1 = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{2} + 2 πn + 1

x - 1 = \frac{3 π}{2} + 2 πn

将

1

到右边

x - 1 = \frac{3 π}{2} + 2 πn

两边加上

1

x - 1 + 1 = \frac{3 π}{2} + 2 πn + 1

化简

x = \frac{3 π}{2} + 2 πn + 1

x = \frac{3 π}{2} + 2 πn + 1

x = \frac{π}{2} + 2 πn + 1, x = \frac{3 π}{2} + 2 πn + 1

作图

流行的例子

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