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人気のある三角関数 >

(sin(42))/(22)=(sin(B))/(12)

解

\frac{sin ( 4 2 ^{\circ} )}{22} = \frac{sin ( B )}{12}

解

B = 0.37361 \dots + 36 0^{\circ} n, B = 18 0^{\circ} - 0.37361 \dots + 36 0^{\circ} n

+1

ラジアン

B = 0.37361 \dots + 2 πn, B = π - 0.37361 \dots + 2 πn

解答ステップ

\frac{sin ( 4 2 ^{\circ} )}{22} = \frac{sin ( B )}{12}

辺を交換する

\frac{sin ( B )}{12} = \frac{sin ( 4 2 ^{\circ} )}{22}

以下で両辺を乗じる:

12

\frac{sin ( B )}{12} = \frac{sin ( 4 2 ^{\circ} )}{22}

以下で両辺を乗じる:

12

\frac{12 sin ( B )}{12} = \frac{12 sin ( 4 2 ^{\circ} )}{22}

簡素化

sin (B) = \frac{6 sin ( 4 2 ^{\circ} )}{11}

sin (B) = \frac{6 sin ( 4 2 ^{\circ} )}{11}

三角関数の逆数プロパティを適用する

sin (B) = \frac{6 sin ( 4 2 ^{\circ} )}{11}

以下の一般解

sin (B) = \frac{6 sin ( 4 2 ^{\circ} )}{11}

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

B = arcsin (\frac{6 sin ( 4 2 ^{\circ} )}{11}) + 36 0^{\circ} n, B = 18 0^{\circ} - arcsin (\frac{6 sin ( 4 2 ^{\circ} )}{11}) + 36 0^{\circ} n

B = arcsin (\frac{6 sin ( 4 2 ^{\circ} )}{11}) + 36 0^{\circ} n, B = 18 0^{\circ} - arcsin (\frac{6 sin ( 4 2 ^{\circ} )}{11}) + 36 0^{\circ} n

10進法形式で解を証明する

B = 0.37361 \dots + 36 0^{\circ} n, B = 18 0^{\circ} - 0.37361 \dots + 36 0^{\circ} n

グラフ

人気の例

sin (θ) = \frac{16}{14}

tan (θ) = \frac{83}{47}

solvefor x,2sin(x)-cos(x)sin(x)=0

so l v e f or x, 2 sin (x) - cos (x) sin (x) = 0

5 = 5 sin (4 θ)

cos(x)=(cos(x))/(csc(x))

cos (x) = \frac{cos ( x )}{csc ( x )}