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verificar sin^2(θ)(1+cot^2(θ))=1

Solución

verificar

sin^{2} (θ) (1 + cot^{2} (θ)) = 1

Verdadero

Pasos de solución

sin^{2} (θ) (1 + cot^{2} (θ)) = 1

Manipular el lado derecho

sin^{2} (θ) (1 + cot^{2} (θ))

Expresar con seno, coseno

(1 + cot^{2} (θ)) sin^{2} (θ)

Utilizar la identidad trigonométrica básica:

cot (x) = \frac{cos ( x )}{sin ( x )}

= (1 + (\frac{cos ( θ )}{sin ( θ )})^{2}) sin^{2} (θ)

Simplificar

(1 + (\frac{cos ( θ )}{sin ( θ )})^{2}) sin^{2} (θ) : sin^{2} (θ) + cos^{2} (θ)

(1 + (\frac{cos ( θ )}{sin ( θ )})^{2}) sin^{2} (θ)

Aplicar las leyes de los exponentes:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= sin^{2} (θ) (\frac{cos ^{2} ( θ )}{sin ^{2} ( θ )} + 1)

Simplificar

1 + \frac{cos ^{2} ( θ )}{sin ^{2} ( θ )}

en una fracción:

\frac{sin ^{2} ( θ ) + cos ^{2} ( θ )}{sin ^{2} ( θ )}

1 + \frac{cos ^{2} ( θ )}{sin ^{2} ( θ )}

Convertir a fracción:

1 = \frac{1 sin ^{2} ( θ )}{sin ^{2} ( θ )}

= \frac{1 \cdot sin ^{2} ( θ )}{sin ^{2} ( θ )} + \frac{cos ^{2} ( θ )}{sin ^{2} ( θ )}

Ya que los denominadores son iguales, combinar las fracciones:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot sin ^{2} ( θ ) + cos ^{2} ( θ )}{sin ^{2} ( θ )}

Multiplicar:

1 \cdot sin^{2} (θ) = sin^{2} (θ)

= \frac{sin ^{2} ( θ ) + cos ^{2} ( θ )}{sin ^{2} ( θ )}

= \frac{sin ^{2} ( θ ) + cos ^{2} ( θ )}{sin ^{2} ( θ )} sin^{2} (θ)

Multiplicar fracciones:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( sin ^{2} ( θ ) + cos ^{2} ( θ ) ) sin ^{2} ( θ )}{sin ^{2} ( θ )}

Eliminar los terminos comunes:

sin^{2} (θ)

= sin^{2} (θ) + cos^{2} (θ)

= sin^{2} (θ) + cos^{2} (θ)

= cos^{2} (θ) + sin^{2} (θ)

Re-escribir usando identidades trigonométricas

cos^{2} (θ) + sin^{2} (θ)

Utilizar la identidad pitagórica:

cos^{2} (x) + sin^{2} (x) = 1

= 1

= 1

Se demostró que ambos lados pueden tomar la misma forma

\Rightarrow Verdadero