化简 (4+3i)/(3-2i)

解答

化简

\frac{4 + 3 i}{3 - 2 i}

\frac{6}{13} + \frac{17}{13} i

求解步骤

\frac{4 + 3 i}{3 - 2 i}

乘以共轭根式

\frac{3 + 2 i}{3 + 2 i}

= \frac{( 4 + 3 i ) ( 3 + 2 i )}{( 3 - 2 i ) ( 3 + 2 i )}

化简

\frac{( 4 + 3 i ) ( 3 + 2 i )}{( 3 - 2 i ) ( 3 + 2 i )} : \frac{6 + 17 i}{13}

= \frac{6 + 17 i}{13}

Rewrite in standard complex form:

\frac{6}{13} + \frac{17}{13} i

= \frac{6}{13} + \frac{17}{13} i