solvefor x,kx^2+x+k=0

Lösung

x, k x^{2} + x + k = 0

x = \frac{- 1 + 1 - 4 k ^{2}}{2 k}, x = \frac{- 1 - 1 - 4 k ^{2}}{2 k}; k \neq = 0

Schritte zur Lösung

k x^{2} + x + k = 0

Löse mit der quadratischen Formel

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 kk}{2 k}

Vereinfache

1^{2} - 4 kk : 1 - 4 k^{2}

x_{1, 2} = \frac{- 1 \pm 1 - 4 k ^{2}}{2 k}; k \neq = 0

Trenne die Lösungen

x_{1} = \frac{- 1 + 1 - 4 k ^{2}}{2 k}, x_{2} = \frac{- 1 - 1 - 4 k ^{2}}{2 k}

x = \frac{- 1 + 1 - 4 k ^{2}}{2 k}; k \neq = 0

x = \frac{- 1 - 1 - 4 k ^{2}}{2 k}; k \neq = 0

Die Lösungen für die quadratische Gleichung sind:

x = \frac{- 1 + 1 - 4 k ^{2}}{2 k}, x = \frac{- 1 - 1 - 4 k ^{2}}{2 k}; k \neq = 0

x^{2} - 10 = 5

f a c t or 3 x^{2} + 10 x = 8

5 x^{2} + 8 x + 1 = 0

x^{2} - 18 x - 4.95 = 0

so l v e f or x, x^{2} - x y + y^{2} = 0