\sqrt[x]{27}=3^{x+2}

Lösung

x 27 = 3^{x + 2}

x = 1, x = - 3

Schritte zur Lösung

x 27 = 3^{x + 2}

Wende Exponentenregel an

\frac{3}{x} = x + 2

Löse

\frac{3}{x} = x + 2 : x = 1, x = - 3

x = 1, x = - 3

6^{x + 2} + 6^{x} = 222

2^{4 x + 2} - 48 \cdot 2^{2 x - 2} + 8 = 0

3 e^{2 x - 3} - 4 = 78

5^{x} = 12 5^{x + 1}

so l v e f or y, x = 1 - e^{- λ \cdot y}