y^{''}-6y^'+34y=0

Lösung

y^{^{''}} - 6 y^{^{'}} + 34 y = 0

y = e^{3 t} (c_{1} cos (5 t) + c_{2} sin (5 t))

Schritte zur Lösung

y^{''} (t) - 6 y^{'} (t) + 34 y = 0

Solve linear ODE:

y = e^{3 t} (c_{1} cos (5 t) + c_{2} sin (5 t))

y = e^{3 t} (c_{1} cos (5 t) + c_{2} sin (5 t))

\frac{\partial}{\partial x} (\frac{1}{3} x^{3})

\int_{- 1}^{2} (7 - 3 t) d t

s l o p e in t erce pt (- 7, - 3), (- 5, - 8)

t an g e n t 2 - x^{2}

\frac{d}{d t} (a cos (w (t) t) + b sin (w (t) t))