What is the derivative of (sqrt(x-1)/(sqrt(x+1))) ?

The derivative of (sqrt(x-1)/(sqrt(x+1))) is 1/(sqrt(x-1)(x+1)^{3/2)}

What is the first derivative of (sqrt(x-1)/(sqrt(x+1))) ?

The first derivative of (sqrt(x-1)/(sqrt(x+1))) is 1/(sqrt(x-1)(x+1)^{3/2)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

\frac{d}{d x} (\frac{x - 1}{x + 1})

\frac{1}{x - 1 ( x + 1 ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{x - 1}{x + 1})

Simplify

\frac{x - 1}{x + 1} : \frac{x - 1}{x + 1}

= \frac{d}{d x} (\frac{x - 1}{x + 1})

Apply the chain rule:

\frac{1}{2 \frac{x - 1}{x + 1}} \frac{d}{d x} (\frac{x - 1}{x + 1})

= \frac{1}{2 \frac{x - 1}{x + 1}} \frac{d}{d x} (\frac{x - 1}{x + 1})

\frac{d}{d x} (\frac{x - 1}{x + 1}) = \frac{2}{( x + 1 ) ^{2}}

= \frac{1}{2 \frac{x - 1}{x + 1}} \cdot \frac{2}{( x + 1 ) ^{2}}

Simplify

\frac{1}{2 \frac{x - 1}{x + 1}} \cdot \frac{2}{( x + 1 ) ^{2}} : \frac{1}{x - 1 ( x + 1 ) ^{\frac{3}{2}}}

= \frac{1}{x - 1 ( x + 1 ) ^{\frac{3}{2}}}

What is the derivative of (sqrt(x-1)/(sqrt(x+1))) ?
The derivative of (sqrt(x-1)/(sqrt(x+1))) is 1/(sqrt(x-1)(x+1)^{3/2)}
What is the first derivative of (sqrt(x-1)/(sqrt(x+1))) ?
The first derivative of (sqrt(x-1)/(sqrt(x+1))) is 1/(sqrt(x-1)(x+1)^{3/2)}