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人気のある微分積分 >

derivative of 2cos(x+1)

解

\frac{d}{d x} (2 cos (x) + 1)

解

- 2 sin (x)

解答ステップ

\frac{d}{d x} (2 cos (x) + 1)

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 cos (x)) + \frac{d}{d x} (1)

\frac{d}{d x} (2 cos (x)) = - 2 sin (x)

\frac{d}{d x} (1) = 0

= - 2 sin (x) + 0

簡素化

= - 2 sin (x)

グラフ

人気の例

integral of (sin(2χ+1))/((cos(2χ+1))^2)

\int \frac{sin ( 2 χ + 1 )}{( cos ( 2 χ + 1 ) ) ^{2}} d χ

integral from 2 to 10 of 1/(x-1)

\int_{2}^{10} \frac{1}{x - 1} d x

integral of 1/(sqrt(16+4x-2x^2))

\int \frac{1}{16 + 4 x - 2 x ^{2}} d x

integral from 1 to 6 of 2pix(-3/2 x+9)

\int_{1}^{6} 2 π x (- \frac{3}{2} x + 9) d x

tangent (sqrt(x)+1)/(sqrt(x)+2)

t an g e n t \frac{x + 1}{x + 2}