What is the derivative of 40ln(3x+1)-x/3 ?

The derivative of 40ln(3x+1)-x/3 is (120)/(3x+1)-1/3

What is the first derivative of 40ln(3x+1)-x/3 ?

The first derivative of 40ln(3x+1)-x/3 is (120)/(3x+1)-1/3

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derivative of

40 ln (3 x + 1) - \frac{x}{3}

\frac{120}{3 x + 1} - \frac{1}{3}

Solution steps

\frac{d}{d x} (40 ln (3 x + 1) - \frac{x}{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (40 ln (3 x + 1)) - \frac{d}{d x} (\frac{x}{3})

\frac{d}{d x} (40 ln (3 x + 1)) = \frac{120}{3 x + 1}

\frac{d}{d x} (\frac{x}{3}) = \frac{1}{3}

= \frac{120}{3 x + 1} - \frac{1}{3}

What is the derivative of 40ln(3x+1)-x/3 ?
The derivative of 40ln(3x+1)-x/3 is (120)/(3x+1)-1/3
What is the first derivative of 40ln(3x+1)-x/3 ?
The first derivative of 40ln(3x+1)-x/3 is (120)/(3x+1)-1/3