What is the integral from-1 to 8 of 1/(\sqrt[3]{x)} ?

The integral from-1 to 8 of 1/(\sqrt[3]{x)} is 9/2

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integral from-1 to 8 of 1/(\sqrt[3]{x)}

\frac{9}{2}

Decimal

4.5

Solution steps

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= - \frac{3 ( - 1 ) ^{\frac{2}{3}}}{2} + 6

Simplify

- \frac{3 ( - 1 ) ^{\frac{2}{3}}}{2} + 6 : \frac{9}{2}

= \frac{9}{2}

What is the integral from-1 to 8 of 1/(\sqrt[3]{x)} ?
The integral from-1 to 8 of 1/(\sqrt[3]{x)} is 9/2