What is the derivative of 1/(x^2+2x+1) ?

The derivative of 1/(x^2+2x+1) is -2/((x+1)^3)

What is the first derivative of 1/(x^2+2x+1) ?

The first derivative of 1/(x^2+2x+1) is -2/((x+1)^3)

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\frac{d}{d x} (\frac{1}{x ^{2} + 2 x + 1})

- \frac{2}{( x + 1 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{1}{x ^{2} + 2 x + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x^{2} + 2 x + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( x ^{2} + 2 x + 1 ) ^{2}} \frac{d}{d x} (x^{2} + 2 x + 1)

= - \frac{1}{( x ^{2} + 2 x + 1 ) ^{2}} \frac{d}{d x} (x^{2} + 2 x + 1)

\frac{d}{d x} (x^{2} + 2 x + 1) = 2 x + 2

= - \frac{1}{( x ^{2} + 2 x + 1 ) ^{2}} (2 x + 2)

Simplify

- \frac{1}{( x ^{2} + 2 x + 1 ) ^{2}} (2 x + 2) : - \frac{2}{( x + 1 ) ^{3}}

= - \frac{2}{( x + 1 ) ^{3}}

What is the derivative of 1/(x^2+2x+1) ?
The derivative of 1/(x^2+2x+1) is -2/((x+1)^3)
What is the first derivative of 1/(x^2+2x+1) ?
The first derivative of 1/(x^2+2x+1) is -2/((x+1)^3)