inverselaplace ((e^{-3s}))/(s^2)

Lösung

inverse laplace transformation

\frac{( e ^{- 3 s} )}{s ^{2}}

H (t - 3) (t - 3)

Schritte zur Lösung

L^{- 1} {\frac{( e ^{- 3 s} )}{s ^{2}}}

Wende inverse Transformationsregel an: if

L^{- 1} {F (s)} = f (t)

dann

L^{- 1} {e^{- a s} F (s)} = H (t - a) f (t - a)

H (t)

Heaviside (Schritt) Funktion ist

= H (t - 3) L^{- 1} {\frac{1}{s ^{2}}} (t - 3)

L^{- 1} {\frac{1}{s ^{2}}} : t

= H (t - 3) (t - 3)

\frac{\partial}{\partial y} (3 x + x^{2} y)

\frac{d y}{d x} = \frac{( 2 x ( y - 2 ) )}{x ^{2} + 1}, y (0) = 4

t \to 0 lim (e^{- t})

d er i v a t i v e y = \frac{1}{2} (e^{x} + e^{- x})

\int 2 x (x^{2} - 7)^{99} d x