What is the tangent of f(x)=(x^3)/2 ,\at x=-6 ?

The tangent of f(x)=(x^3)/2 ,\at x=-6 is y=54x+216

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tangent of f(x)=(x^3)/2 ,\at x=-6

tangent of

f (x) = \frac{x ^{3}}{2}, at x = - 6

y = 54 x + 216

Solution steps

Find the tangent point:

(- 6, - 108)

Find the slope of

f (x) = \frac{x ^{3}}{2} : \frac{df ( x )}{d x} = \frac{3 x ^{2}}{2}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 54

Find the line with slope m=

54

and passing through

(- 6, - 108) : y = 54 x + 216

y = 54 x + 216

What is the tangent of f(x)=(x^3)/2 ,\at x=-6 ?
The tangent of f(x)=(x^3)/2 ,\at x=-6 is y=54x+216