What is the integral of ((2+x^2))/(sqrt(x)) ?

The integral of ((2+x^2))/(sqrt(x)) is 4sqrt(x)+2/5 x^{5/2}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of ((2+x^2))/(sqrt(x))

\int \frac{( 2 + x ^{2} )}{x} d x

4 x + \frac{2}{5} x^{\frac{5}{2}} + C

Solution steps

\int \frac{2 + x ^{2}}{x} d x

Expand

\frac{2 + x ^{2}}{x} : \frac{2}{x} + x^{\frac{3}{2}}

= \int \frac{2}{x} + x^{\frac{3}{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2}{x} d x + \int x^{\frac{3}{2}} d x

\int \frac{2}{x} d x = 4 x

\int x^{\frac{3}{2}} d x = \frac{2}{5} x^{\frac{5}{2}}

= 4 x + \frac{2}{5} x^{\frac{5}{2}}

Add a constant to the solution

= 4 x + \frac{2}{5} x^{\frac{5}{2}} + C

What is the integral of ((2+x^2))/(sqrt(x)) ?
The integral of ((2+x^2))/(sqrt(x)) is 4sqrt(x)+2/5 x^{5/2}+C