What is the integral of x^4+7sqrt(x) ?

The integral of x^4+7sqrt(x) is (x^5)/5+14/3 x^{3/2}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of x^4+7sqrt(x)

\int x^{4} + 7 x d x

\frac{x ^{5}}{5} + \frac{14}{3} x^{\frac{3}{2}} + C

Solution steps

\int x^{4} + 7 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{4} d x + \int 7 x d x

\int x^{4} d x = \frac{x ^{5}}{5}

\int 7 x d x = \frac{14}{3} x^{\frac{3}{2}}

= \frac{x ^{5}}{5} + \frac{14}{3} x^{\frac{3}{2}}

Add a constant to the solution

= \frac{x ^{5}}{5} + \frac{14}{3} x^{\frac{3}{2}} + C

What is the integral of x^4+7sqrt(x) ?
The integral of x^4+7sqrt(x) is (x^5)/5+14/3 x^{3/2}+C