integral of (3x+2)/(x^2+9)

Lösung

\int \frac{3 x + 2}{x ^{2} + 9} d x

\frac{3}{2} ln x^{2} + 9 + \frac{2}{3} arctan (\frac{x}{3}) + C

Schritte zur Lösung

\int \frac{3 x + 2}{x ^{2} + 9} d x

Multipliziere aus

\frac{3 x + 2}{x ^{2} + 9} : \frac{3 x}{x ^{2} + 9} + \frac{2}{x ^{2} + 9}

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{3 x}{x ^{2} + 9} d x + \int \frac{2}{x ^{2} + 9} d x

\int \frac{3 x}{x ^{2} + 9} d x = \frac{3}{2} ln x^{2} + 9

\int \frac{2}{x ^{2} + 9} d x = \frac{2}{3} arctan (\frac{x}{3})

= \frac{3}{2} ln x^{2} + 9 + \frac{2}{3} arctan (\frac{x}{3})

Füge eine Konstante zur Lösung hinzu

= \frac{3}{2} ln x^{2} + 9 + \frac{2}{3} arctan (\frac{x}{3}) + C