integral from 0 to pi/6 of 3cos(x)+1

解

\int_{0}^{\frac{π}{6}} 3 cos (x) + 1 d x

\frac{3}{2} + \frac{π}{6}

十進法表記

2.02359 \dots

解答ステップ

\int_{0}^{\frac{π}{6}} 3 cos (x) + 1 d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{\frac{π}{6}} 3 cos (x) d x + \int_{0}^{\frac{π}{6}} 1 d x

\int_{0}^{\frac{π}{6}} 3 cos (x) d x = \frac{3}{2}

\int_{0}^{\frac{π}{6}} 1 d x = \frac{π}{6}

= \frac{3}{2} + \frac{π}{6}