integral from 0 to 3 of-x^2+4x

Lösung

\int_{0}^{3} - x^{2} + 4 x d x

9

Schritte zur Lösung

\int_{0}^{3} - x^{2} + 4 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{3} x^{2} d x + \int_{0}^{3} 4 x d x

\int_{0}^{3} x^{2} d x = 9

\int_{0}^{3} 4 x d x = 18

= - 9 + 18

Vereinfache

= 9

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