integral from 1 to 2x-1 of e^t

Lösung

\int_{1}^{2 x - 1} e^{t} d t

e^{2 x - 1} - e

Schritte zur Lösung

\int_{1}^{2 x - 1} e^{t} d t

Nutze das gemeinsame Integral :

\int e^{t} d t = e^{t}

= [e^{t}]_{1}^{2 x - 1}

Berechne die Grenzen:

e^{2 x - 1} - e

= e^{2 x - 1} - e

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