integral from-8 to 9 of (1-x)

Lösung

\int_{- 8}^{9} (1 - x) d x

\frac{17}{2}

Dezimale

8.5

Schritte zur Lösung

\int_{- 8}^{9} 1 - x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 8}^{9} 1 d x - \int_{- 8}^{9} x d x

\int_{- 8}^{9} 1 d x = 17

\int_{- 8}^{9} x d x = \frac{17}{2}

= 17 - \frac{17}{2}

Vereinfache

17 - \frac{17}{2} : \frac{17}{2}

= \frac{17}{2}