What is the solution for x^{''}+9x=27,x(0)=4,x^'(0)=6 ?

The solution for x^{''}+9x=27,x(0)=4,x^'(0)=6 is x=cos(3t)+2sin(3t)+3

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x^{''}+9x=27,x(0)=4,x^'(0)=6

x^{^{''}} + 9 x = 27, x (0) = 4, x^{^{'}} (0) = 6

x = cos (3 t) + 2 sin (3 t) + 3

Solution steps

x^{''} (t) + 9 x = 27

Solve linear ODE:

x = cos (3 t) + 2 sin (3 t) + 3

x = cos (3 t) + 2 sin (3 t) + 3

What is the solution for x^{''}+9x=27,x(0)=4,x^'(0)=6 ?
The solution for x^{''}+9x=27,x(0)=4,x^'(0)=6 is x=cos(3t)+2sin(3t)+3