What is the derivative of 2x^3-16x^2-2c+4d ?

The derivative of 2x^3-16x^2-2c+4d is 6x^2-32x

What is the first derivative of 2x^3-16x^2-2c+4d ?

The first derivative of 2x^3-16x^2-2c+4d is 6x^2-32x

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\frac{d}{d x} (2 x^{3} - 16 x^{2} - 2 c + 4 d)

6 x^{2} - 32 x

Solution steps

\frac{d}{d x} (2 x^{3} - 16 x^{2} - 2 c + 4 d)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (16 x^{2}) - \frac{d}{d x} (2 c) + \frac{d}{d x} (4 d)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (16 x^{2}) = 32 x

\frac{d}{d x} (2 c) = 0

\frac{d}{d x} (4 d) = 0

= 6 x^{2} - 32 x - 0 + 0

Simplify

= 6 x^{2} - 32 x

What is the derivative of 2x^3-16x^2-2c+4d ?
The derivative of 2x^3-16x^2-2c+4d is 6x^2-32x
What is the first derivative of 2x^3-16x^2-2c+4d ?
The first derivative of 2x^3-16x^2-2c+4d is 6x^2-32x